M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
Answer:
-2
Step-by-step explanation:
that is were the x is zero
Answer:
A
Step-by-step explanation:
When:
a = b = 0 we have point (0,0).
a = 0 and b ≠ 0 vertical line segment from (0, -b) to (0, b)
a ≠ 0 and b = 0 horizontal line segment from (-a, 0) to (a, 0)
a ≠ 0 and b ≠ 0 a ≠ b ellipse
a ≠ 0 and b ≠ 0 a = b circle
