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zhenek [66]
3 years ago
15

Matthew and Ava have some money in the ratio 5:2. If Matthew gives $78 to Ava they will have the same amount of money. How much

money do they have altogether?
Mathematics
1 answer:
Rashid [163]3 years ago
8 0

Answer:

is d

Step-by-step explanation:

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Selena's family went on a trip. The total hotel bill was $659 . The cost of the airfare was $633. use mental math to find the to
Vilka [71]
659+633

=1292

hope this helps
4 0
4 years ago
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Use the trend line to predict the wind chill at these wind speeds<br> (9 and 10)
vfiekz [6]
First, you need to find the trend line that you are going to use before you can answer question 9 and 10. 

To do that select 2 points from your list and find the y = mx + b equation. 

After you have your equation, all you need to do is plug in the values that you are given for x. Evaluate the expression and you will have your answer.
5 0
3 years ago
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Nathan works for a company that provides props to theater groups. He needs to make a stop sign that is the same size as in real
Nat2105 [25]

Answer:

I believe the answer is 6000 millimeters. I am sorry if this answer is wrong. But I think it may be 6000 or close to it. Again I am super sorry if it is wrong. Have a nice day!!

Step-by-step explanation:

4 0
4 years ago
Find the common ratio 24,18,37/2,81/8
Vinil7 [7]

Note: The third term of the sequence should be \dfrac{27}{2} instead of \dfrac{37}{2}, otherwise the sequence has no common ratio.

Given:

The given sequence is

24,18,\dfrac{27}{2},\dfrac{81}{8}

To find:

The common ratio of the given sequence.

Solution:

The quotient of each pair of consecutive terms are:

\dfrac{18}{24}=\dfrac{3}{4}

Similarly,

\dfrac{\dfrac{27}{2}}{18}=\dfrac{27}{36}

\dfrac{\dfrac{27}{2}}{18}=\dfrac{3}{4}

And,

\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{81}{8}\times \dfrac{2}{27}

\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{3}{4}

Therefore, the common ratio of the given sequence is \dfrac{3}{4} or 0.75.

8 0
3 years ago
What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?
bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram ,  but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= (\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})

Mid point of BD= (\dfrac{-3+2}{2},\dfrac{5+2}{2})=(\dfrac{-1}{2},\dfrac{7}{2})

Thus, Mid point of AC=Mid point of BD

i.e. diagonals bisect each other.

That means ABCD is a parallelogram.

8 0
3 years ago
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