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olchik [2.2K]
3 years ago
10

Find the GCF of 18x2 and 15x5

Mathematics
2 answers:
Feliz [49]3 years ago
8 0

18 × 2 = 9 × 2 × 2 = 3 × 3 × 2 × 2

15 × 5 = 3 × 5 × 5

GCF(18 × 2, 15 × 5) = 3

ikadub [295]3 years ago
3 0

Answer:

3x^2

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Let F and S be the present ages of Father and Son, respectively.

We are told that <u>(F-2) = 9(S-2)</u> [2 years ago, father age was nine times the son age]

We also learn that <u>(F+3) = 5(S+3)</u>  [3 years later it will be 5 times only]

Take the first expression and isolate one of the variables (S or F).  I'll isolate F:

(F-2) = 9(S-2)

F = 9S - 16

Now use this in the second expression:

(F+3) = 5(S+3)

((9S-16)+3) = 5(S+3)

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4S = 28

S = 7

Since F = 9S-16,

F = 9*(7)-16

F = 47

<u><em>Father is 47 and Son is 7</em></u>

CHECK:

Was the father 9 times the age of his son 2 years ago?

Father would have been 45 and son 5.  Yes, 9*5 = 45

In 3 years will he be 5 times older than his son?  Yes, Father would be 50 and son would be 10.  5*(10) = 50

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If you know two points on a line how can you find the rate of change of the variables being graphed
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Step-by-step explanation:

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Hello,
-a²+12a=0
a²-12a=0
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Find all the solutions of the equation in the interval [0,2pi). 4sin^(2)x=5-4cosx
gulaghasi [49]
                       4sin²(x) = 5 - 4cos(x)
        4{¹/₂[1 - cos(2x)]} = 5 - 4cos(x)
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         4[¹/₂ - ¹/₂cos(2x)] = 5 - 4cos(x)
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               -4cos²(x) + 2 = 3 - 4cos(x)
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                            2         2
                         cos(x) = ¹/₂
                cos⁻¹[cos(x)] = cos⁻¹(¹/₂)
                                 x = 60, 300
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[0, 2π) = 0 ≤ x < 2π
[0, 2π) = 0 ≤ π/3 ≤ 2π or 0 ≤ 5pi/3 < 2π
5 0
3 years ago
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