Answer:
(-2,-2) and (3,4)
Step-by-step explanation:
Edge 2020
Answer:
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Step-by-step explanation:
Given that M is a polynomial of degree 3.
So, it has three zeros.
Let the polynomial be
M(x) =a(x-p)(x-q)(x-r)
The two zeros of the polynomial are -4 and 4i.
Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.
Then,
M(x)= a{x-(-4)}(x-4i){x-(-4i)}
=a(x+4)(x-4i)(x+4i)
=a(x+4){x²-(4i)²} [ applying the formula (a+b)(a-b)=a²-b²]
=a(x+4)(x²-16i²)
=a(x+4)(x²+16) [∵i² = -1]
=a(x³+4x²+16x+64)
Again given that M(0)= 53.12 . Putting x=0 in the polynomial
53.12 =a(0+4.0+16.0+64)

=0.83
Therefore the required polynomial is
M(x)=0.83(x³+4x²+16x+64)
Answer:
4/8 = 20/x
20 x 8 = 160
160 ÷ 4 = 40
the student will attend 40 weeks of school
Answer:
ok send me the questions
Step-by-step explanation:
The formula for the sum of the a finite geometric series is this:
Sn = a((1-r^n) / (1-r))
The given values are:
n = 30
a = 0.5 mi
r = 1.10 (10% more each day)
S30 = 0.5 ((1-1.10^30) / (1-1.10))
S30 = 82.25 mi
After 30 days, he will have traveled 82.25 miles.