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alexira [117]
3 years ago
15

NEED HELP ASAP.....At the 2012 Summer Olympic Games in London, in the Men's Shot Put qualifying round, the distances ranged from

17.58 meters to 21.36 meters with a mean distance of 19.64 meters and a standard deviation equal to 0.92 meters. If the distribution were truly a normal distribution, what percent of the athletes would have had a distance greater than 20.56 meters, one standard deviation above the mean? There were 40 athletes in the competition. How many athletes does that represent?
OPTIONS:
-about 6 athletes
-about 14 athletes
-about 20 athletes
-about 26 athletes
-about 34 athletes
Mathematics
1 answer:
jeka57 [31]3 years ago
6 0

Answer:

About 6 athletes.

Step-by-step explanation:

We are concerned only with the percent of athletes that are above one standard deviation.

Between one standard deviation and two standard deviations, there is 13.6% of the athletes.

From 2 to 3, there is 2.1%. Above 3, there is 0.2%.

The sum of those percentages is 15.9% of 40 = 0.159 · 40 = 6.36 or about 6 athletes.

Hope this helps.

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Paul has $30,000 to invest. His intent is to earn 15% interest on his investment. He can invest part of his money at 8% interest
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Step-by-step explanation:

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