The perimeter of a rectangle is 150cm. The length is 15cm greater than the width. Find the dimensions

1 answer:

7 0

150/4 = 37.5cm. You divide by four because there are four sides on a rectangle. But 37.5 is the cm of a square. Since it says one of the sides is 15cm greater, you subtract 37.5 - 15 = 27.5cm on 2 of the width. While the other 2 lengths are greater than the width by 15 cm, so you add 15 to 37.5 which gives you 52.5cm. So the 2 width are 27.5cm and the length is 52.5cm.

You might be interested in

Help me solve this questions with steps please

Flauer [41]

Answer:

Step-by-step explanation:

Since the triangle is right use the tangent ratio to find x

tan22° = $\frac{opposite}{adjacent}$ = $\frac{203}{x}$

Multiply both sides by x

x × tan22° = 203 ( divide both sides by tan22° )

x = $\frac{203}{tan22}$ ≈ 502.5 m → B

7 0

3 years ago

The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two

Cloud [144]

Answer:

Step-by-step explanation:

A. Two measurements(AandB)are taken on the same round.\oIs there a difference in the measurement of the muzzle velocity between device A and device B at the α=0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers.

B. Construct a 99% confidence interval about the population mean difference. Compute the difference as device A minus device B. Interpret your results. The confidence interval is (__,__)?

Answer:

Open chart in StatCrunch --- Stat --- T Stats --- Paired --- Enter values: Sample 1 = A, Sample 2 = B --- Click on Confidence Interval… and enter Level which is my #%. --- Compute

7 0

3 years ago

Help me with this please

Klio2033 [76]

Answer:

No, she's wrong

$x\leq\frac{2}{5}$