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4 years ago

PLZ HELP 20 POINTS!!!!!!!! WILL PUT BRAINLIEST!!!!!!!!!!!

Mathematics

2 answers:

sashaice [31]4 years ago

6 0

I think is B but I have to work this out

LenKa [72]4 years ago

3 0

Answer:

yes the correct answer is B

Step-by-step explanation:

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7x-3=-3+7x i neep help answer this please

erica [24]

Answer:

All real numbers are solutions.

Step-by-step explanation:

Let's solve your equation step-by-step.

7x− 3 = − 3 + 7x

Step 1: Simplify both sides of the equation.

7x − 3 = −3 + 7x

7x + −3 = −3 + 7x

7x − 3 = 7x − 3

Step 2: Subtract 7x from both sides.

7x− 3 −7x = 7x −3 −7x

−3 = −3

Step 3: Add 3 to both sides.

−3 + 3 = −3 + 3

0 = 0

7 0

3 years ago

Read 2 more answers

What values of x makes -6x =12 true<br>

Licemer1 [7]

Answer:

Step-by-step explanation:

hope it's helpful :-)

8 0

3 years ago

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What’s bigger kbps or mbps?

leva [86]

KBPS is larger than MBPS.

1 KBPS = 0.001 MBPS

6 0

4 years ago

Read 2 more answers

(−7c+8d)0.6 distributive property

Ksivusya [100]

We are given

$(-7c+8d)0.6$

we can use distribute property

Distributive property:

$(A+B)C=A*C+B*C$

so, we can write it as

$(-7c+8d)0.6=-7c*0.6+8d*0.6$

$(-7c+8d)0.6=-7*0.6c+8*0.6d$

now, we can multiply terms

and we get

$(-7c+8d)0.6=-4.2c+4.8d$ ..............Answer

4 0

3 years ago

Read 2 more answers

An automobile company wants to determine the average amount of time it takes a machine to assemble a car. A sample of 40 times y

aksik [14]

Answer:

A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

Step-by-step explanation:

We are given that a sample of 40 times yielded an average time of 23.92 minutes, with a sample standard deviation of 6.72 minutes.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average time = 23.92 minutes

s = sample standard deviation = 6.72 minutes

n = sample of times = 40

$\mu$ = population mean assembly time

<em> Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation. </em>

<u>So, a 98% confidence interval for the population mean, </u> $\mu$ <u> is; </u>

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

of significance are -2.426 & 2.426}

P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

<u>98% confidence interval for</u> $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

7 0

3 years ago