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3 years ago

Wha equivalent to -5+-3

Mathematics

2 answers:

Sergeeva-Olga [200]3 years ago

8 0

Equivalent is somewhat the same thing as just adding them so -5+-3 is -8

Nitella [24]3 years ago

7 0

-5 + -3 the answer is -8 because its just like adding

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A professor of statistics wants to test that the average amount of money a typical college student spends per day during spring

solniwko [45]

Answer it is 456y5445t6y5432

Step-by-step explanation:

8 0

3 years ago

e vertices of a rectangle are R(-5,-5), S(-6,-5),T(-1,1),U(-5,1) a translation maps R to the point (2,-9)

Tema [17]

Answer:

The rule of translation : $(x,y)\rightarrow (x+7,y-4)$

The vertices of image is R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

Step-by-step explanation:

The vertices of a rectangle are R(-5,-5), S(-6,-5), T(-1,1), U(-5,1).

It is given that a translation maps R to the point (2,-9).

Difference between x-coordinates:

$-5-2=-7$

Difference between y-coordinates:

$-5-(-9)=-5+9=4$

The x-coordinate increased by 7 and y-coordinate decreased by 4. It means the figure shifts 7 units right and 4 units down.

The rule of translation is

$(x,y)\rightarrow (x+7,y-4)$

The vertices of image are

$R(-5,-5)\rightarrow R'(-5+7,-5-4)=R'(2,-9)$

$S(-6,-5)\rightarrow S'(-6+7,-5-4)=S'(1,-9)$

$T(-1,1)\rightarrow T'(-1+7,1-4)=T'(6,-3)$

$U(-5,1)\rightarrow U'(-5+7,1-4)=U'(2,-3)$

Therefore, the vertices of image are R'(2,-9), S'(1,-9), T'(6,-3) and U'(2,-3).

7 0

3 years ago

During a period of extreme cold, the average daily temperature dropped decreased by 112°F day. How many days did it take for the

NNADVOKAT [17]

It takes about 4 days for the temperature to decrease by 9°F.

An equation is an expression that shows the relationship between two or more variables or numbers.

Let x represent the number of days. Given that the temperature drop decreased by 1 1/2°F each day (- 1 1/2), for it to decrease by 9°F (-9):

-1 1/2 * x = -9

-1.5x = - 9

x = 4 days

It takes about 4 days for the temperature to decrease by 9°F.

5 0

2 years ago

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm

sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

$\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}$

And now, 15 degrees is 11 times smaller than the other

Then other angle = 11 times of 15 degrees

$\text {Other angle }=11 \times 15=165 \text { degrees }$

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

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3 years ago

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finlep [7]

Answer:

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3 years ago