6x^2-5x+5 =0 <br> Quadratic formula

A triangle is rotated 90° about the origin. Which rule describes the transformation?

Alla [95]

Answer: The rule (x,y)=(y,-x) describes the

transformation

Step-by-step explanation:.........bc

4 0

3 years ago

...................................................

ikadub [295]

Answer:

chicken nuggies

Step-by-step explanation:

4 0

3 years ago

The capacity of an elevator is 12 people or 2088 pounds. the capacity will be exceeded if 12 people have weights with a mean gre

boyakko [2]

suppose the people have weights that are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Find the probability that if a person is randomly selected, his weight will be greater than 174 pounds?

Assume that weights of people are normally distributed with a mean of 177 lb and a standard deviation of 26 lb.

Mean = 177

standard deviation = 26

We find z-score using given mean and standard deviation

z = $\frac{x-mean}{standard deviation}$

= $\frac{174-177}{26}$

=-0.11538

Probability (z>-0.11538) = 1 - 0.4562 (use normal distribution table)

= 0.5438

P(weight will be greater than 174 lb) = 0.5438

8 0

3 years ago

Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

3 years ago

What is the solution to the system of equations? you must show all work to recieve full credit!

earnstyle [38]

Use the substitution method:
2x - 6y = -12
x - 2y = -8
Then x = 2y - 8
Substitute in the first equation:
2(2y - 8) - 6y = -12
4y - 16 - 6y = -12
-2y = 4
y = -2
Now substitute y in one of the two equations given you prefer:
For example x-2*(-2) = -8
x + 4 = -8
x = -12
The solutions are x = -12 and y = -2

5 0

3 years ago

6x^2-5x+5 =0 Quadratic formula