Question

write an equation of a line that is perpendicular to given line that passes through the given point 5y+2x=-15 T(5,-5)​

Answer 1

Step-by-step explanation:

The answer is on the bottom if you just wanna scroll down.

The first thing that you would want to do is turn the equation of the given line into slope-intercept form (it's just easier). To do that, you would want to isolate  y on either side. So subtract 2x and divide both sides by 5 and you get: y=-2/5x-3. After you do this, remember that perpendicular lines have the negative reciprical slope of the original line. So since the slope is -2/5, the slope of a perpendicular line would be 5/2. Now you have m=5/2 which is your slope! Now you can use slope point form which is y-y_1=m(x-x_1). You know your m which is 5/2. y-y_1=5/2(x-x_1). Since we know that the line passes through the point (5,-5) we can just plug the numbers in. y-(-5)=5/2(x-5). simplify everything: y+5=5/2(x-5). Remember, math is all about making things simple and easy. since the problem didn't say a specific type of equation, you can just put that as your answer!

Answer:

y+5=5/2(x-5)

Hope this helps! (If it's wrong, plz leave sum comments. thx lol)