3 years ago

What is -35 divided by 7?

Mathematics

2 answers:

jonny [76]3 years ago

6 0

Your answer would be -5

Shkiper50 [21]3 years ago

5 0

-37 divided by 7 = -5

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Are 27.4 ones the same as 274 tenths

nadezda [96]

Yes. You can find that out by multiplying .1 by 274. It equals 27.4.

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3 years ago

Find the product. Write fractions in the simplest form.<br><br> 5/6(-8/15)<br> *

aliina [53]

Answer:

-75/48

Step-by-step explanation:

multiply 5 by 15

and 6 by 8

5x15 is 75 , put it in numerator

6x8 is 48 , denominator

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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marshall27 [118]

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3 years ago

What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c

zysi [14]

Answer:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

Step-by-step explanation:

Given

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Required

Simplify

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}$

Cancel out 18

$\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}$

Divide 4 and 2

$\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}$

Divide 27 and 12 by 3

$\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}$

Apply law of indices

$\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}$

$\frac{9a^5 * b^3 * 2c }{4}$

Divide 2 and 4

$\frac{9a^5 * b^3 * c}{2}$

$\frac{9a^5b^3c}{2}$

Rewrite as:

$\frac{9}{2}a^5b^3c$

Hence:

$\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c$

4 0

3 years ago