Answer:
Cards with Mark = 30
Cards with Drew = 120
Cards with Katie = 12
Step-by-step explanation:
The complete question is
Drew has 4 times as many baseball cards as Mark. Katie has 3 fewer than than half as many cards as Mark. In all they have 162 baseball cards. How many does each have?
Solution -
Let the number of cards with Mark be "X"
Number of cards with Drew = 4 *X = 4X
Number of Cards with Katies = 0.5 X -3
Sum of all the cards is equal to 162
X+4X + 0.5 X -3 = 162
5.5 X = 165
X = 30
Cards with Mark = 30
Cards with Drew = 4 * 30 = 120
Cards with Katei = 15-3 = 12
Answer:
we conclude that an inequality 'c ≥ 5' denotes this situation.
Step-by-step explanation:
Given
- A car dealer ship sells at least 5 minivans
When we talk about 'at least', it means we are talking about '≥' in terms of representing the 'at least' in inequality symbol.
For instance,
'm≥n' means 'm' is greater than or equal to 'n'.
It means 'm' is at least equal to 'n'.
Coming back to the question,
- Let 'c' represent the number of minivans sold each week.
As the car dealer ship sells at least 5 minivans. so the
inequality will be: c ≥ 5
Thus, we conclude that an inequality 'c ≥ 5' denotes this situation.
Answer:
B and C work. A and D do not.
Step-by-step explanation:
This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.
A]
5n + 6
Let n = 1
5(1) + 6
5 + 6= 11
However there is trouble beginning with n = 2
5*2 + 6
10 + 6
16 All you need is one wrong answer and the choice is toast. So A won't work.
================
Try D
6(n - 1)+ 5
n=0
6*(-1) + 5
-6 + 5
- 1
And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse. D is not one of the answers.
=============
B
Let n = 1
6(1) + 5
6 + 5
11 The first term works.
n = 2
6*(2) + 5
12 + 5
17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.
n = 3
6*(3) + 5
18 + 5
23 And this also works. I'll let you deal with n = 4
========
C
n = 0
6(0 + 1) + 5
6*1 + 5
6 + 5
11
n = 1
6(1 + 1) + 5
6*2 + 5
12 + 5
17 which works.
So C is an answer.
