Answer:
20wiwiiwiwjwjajsiwjjwnasjjwnwnwsjajjwjw
90 cm because ................................
I'm not sure about this but will give it a try:
Let f(n) = 2xⁿ - 2
Then f(3) = 2x³ - 2
So, f(2) = 2x² - 2
Lengths are given to 1dp so the biggest that the lengths could be is 4.65cm and 5.35cm. if you use pythagoras on these to find hypotenuse, this is the upper bound.