$\dfrac{x^2-8x+12}{x^2-7x+10}\\\\x^2-7x+10\ne0\ \iff\ x=\frac{7\pm\sqrt{49-40}}{2}\ne0\ \iff\ x\ne5\ \wedge\ x\ne2\\\\\\\dfrac{x^2-8x+12}{x^2-7x+10}=\dfrac{x^2-2x-6x+12}{x^2-2x-5x+10}=\dfrac{x(x-2)-6(x-2)}{x(x-2)-5(x-2)}=\\\\\\ =\dfrac{(x-2)(x-6)}{(x-2)(x-5)}=\dfrac{x-6}{x-5}\\\\\\f(x)=x-6\\\\g(x)=x-5$

4 0

3 years ago

What is the perimeter?

Vladimir79 [104]

Answer:

Perimeter = 22 units

Area = 30 units squared

Step-by-step explanation: To find the perimeter of this figure, add the lengths of the rectangle's four sides (5+6+5+6=22). To find the area of this figure, multiply the length and width of the rectangle (5x6=30).

5 0

2 years ago

P=−4b 2 +6b−9 <br> Q=7b 2 −2b−5<br> P−Q=<br> Your answer should be a polynomial in standard form.

shepuryov [24]

Answer:

−11b^2+8b−4

Step-by-step explanation:

−4b2+6b−9−7b2+2b+5

Simplify by adding terms.

11b2+8b−4

3 0

2 years ago

Use a calculator to evaluate sec 85 degrees

faltersainse [42]

OK. I used my calculator to evaluate sec(85 degrees).

My calculator doesn't have a "sec" button on it.
But I remembered that

sec of an angle = 1 / (cosine of the same angle) .

So I used my calculator to find cos(85), and then I hit the
" 1/x " key, and got 11.474, which I knew to be sec(85).

3 0

3 years ago