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8090 [49]
3 years ago
5

Jason’s savings account has a balance of $2179. After 5 years , what will the amount of interest be at 6% compounded quarterly?

Mathematics
1 answer:
satela [25.4K]3 years ago
5 0

Answer:

$755.80

Step-by-step explanation:

Determine the compound amount first and then subtract the principal from it, to find the amount of interest.

The compound amount formula is A = P (1 + r/n)^(nt), where

P is the initial principal, r is the interest rate as a decimal fraction, n is the number of compounding periods per year, and t is the number of years.  Here, P = $2179; t = 5 yrs; r = 0.06; and n = 4 (quarterly compounding).

We get:

A = $2179(1 + 0.06/4)^(4*5), or $2179(1.015)^20, or $2179(1.347) = $2937.80.

The compound amount is $2934.80.  Subtracting the $2179 principal results in the interest earned:  $755.80.

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IrinaVladis [17]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Solve for |2x + 4|-1=7
Rudik [331]

Answer:

x = - 6 or x = 2

Step-by-step explanation:

The absolute value function always returns a positive value. However, the expression inside can be positive or negative.

Given

| 2x + 4 | - 1 = 7 ( add 1 to both sides )

| 2x + 4 | = 8, thus

2x + 4 = 8 ( subtract 4 from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

OR

-(2x + 4) = 8

- 2x - 4 = 8 ( add 4 to both sides )

- 2x = 12 ( divide both sides by - 2 )

x = - 6

As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

x = 2 → | 4 + 4 | - 1 = | 8 | - 1 = 8 - 1 = 7 ← True

x = - 6 → | - 12 + 4 | - 1 = | - 8 | - 1 = 8 - 1 = 7 ← True

Hence the solutions are x = - 6 or x = 2

6 0
3 years ago
The weight of baby goats is believed to be Normally distributed, with a mean of 5.75 pounds. The average weight of a random samp
Julli [10]

Answer:

The standard error of the mean is 0.0783.

Step-by-step explanation:

The Central Limit Theorem helps us find the standard error of the mean:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

The standard deviation of the sample is the same as the standard error of the mean. So

SE_{M} = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\sigma = 0.35, n = 20

So

SE_{M} = \frac{\sigma}{\sqrt{n}}

SE_{M} = \frac{0.35}{\sqrt{20}}

SE_{M} = 0.0783

The standard error of the mean is 0.0783.

7 0
3 years ago
Find the diameter when the circumference is 47.1 in
MissTica

C = pi x d

3,14 x d = 47,1

d = 15

3 0
2 years ago
Given f(x) = x+2 and g(x) = x-4 solve for (fg)(x)
kirza4 [7]

Answer:  f(g(x)) = x - 2

<u>Step-by-step explanation:</u>

f(x) = x + 2            

g(x) = x - 4

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                       = x - 2                 <em>simplified</em>

6 0
3 years ago
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