Answer:
f^-1(x) = x + 4
Step-by-step explanation:
Answer:
If the expression is
, then the answer is the first option.
If the expression is
, then the answer is the third option.
Step-by-step explanation:
Remember that when you have a radical expression in the form
, you can rewrite as:
![=x^\frac{1}{n}](https://tex.z-dn.net/?f=%3Dx%5E%5Cfrac%7B1%7D%7Bn%7D)
Then:
- If the expression is
, then you can rewrite it in the following radical form:
(This form matches with the first option.)
- If the expression is
, then you can rewrite it in the following radical form:
(This form matches with the third option).
5000 is 1/10 of 50000 because 50000 divided by 10 is 5000
Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,
![f\left(f^{-1}(x)\right) = x](https://tex.z-dn.net/?f=f%5Cleft%28f%5E%7B-1%7D%28x%29%5Cright%29%20%3D%20x)
![\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x](https://tex.z-dn.net/?f=%5Cimplies%20f%5E%7B-1%7D%28x%29%5E3%20-%20f%5E%7B-1%7D%28x%29%20%2B%202%20%3D%20x)
which is a cubic polynomial in
with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).
Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.
f'(x) = 3x² - 1 = 0 ⇒ x = ±1/√3
So, we have three subsets over which f(x) can be considered invertible.
• (-∞, -1/√3)
• (-1/√3, 1/√3)
• (1/√3, ∞)
By the inverse function theorem,
![\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}](https://tex.z-dn.net/?f=%5Cleft%28f%5E%7B-1%7D%5Cright%29%27%28b%29%20%3D%20%5Cdfrac1%7Bf%27%28a%29%7D)
where f(a) = b.
Solve f(x) = 2 for x :
x³ - x + 2 = 2
x³ - x = 0
x (x² - 1) = 0
x (x - 1) (x + 1) = 0
x = 0 or x = 1 or x = -1
Then
can be one of
• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);
• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or
• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)
9514 1404 393
Answer:
r = 1/9
Step-by-step explanation:
First of all, solve the equation for r:
y = rx
y/x = r . . . . . . . divide by x
__
Since r is a constant, it will be the same for any corresponding pairs of x and y. It is convenient to choose both x and y as integers, as in the third table entry.
r = y/x = 5/45
r = 1/9 . . . . . . . . . reduced fraction
_____
<em>Additional comment</em>
It is not a bad idea to check to see that this works with other values of x and y. For the first line of the table, we have x = 11:
y = rx = (1/9)(11) = 11/9 = 1 2/9 . . . . matches the table value