Answer:
yes
Step-by-step explanation:
Answer:
1.068.
Step-by-step explanation:
Use the identity
sec^2 O = 1 + tan^2 O
= 1 + (3/8)^2
= 1 9/64
= 73/64
so sec O = √73/8
= 1 .068.
Answer:
There is an 8.22% probability that a randomly selected person has a birthday in November.
Step-by-step explanation:
The theoretical method to find the probability is the division of the number of desired outcomes by the number of total outcomes.
A randomly selected person has a birthday in November
There are 365 days in a year, so the number of total outcomes is 365.
There are 30 days in november, so the number of desired outcomes is 30.
So the probability is

There is an 8.22% probability that a randomly selected person has a birthday in November.
65 % is bigger than 16/25
For 44
7x2=14
14+8=22
22x2=44
Is this ok, I hope I helped :)