Answer:
- as written: c = P - a - b - d/4
- with parentheses: c = 4P - a - b - d
Step-by-step explanation:
The meaning of the given expression is ...
P = a + b + c + (d/4)
To solve for c, subtract all the terms on the right side not containing c.
P -(a + b + (d/4)) = c
c = P - a - b - (d/4)
_____
In such equations, parentheses are commonly missing. If that is the case here, then first we undo the division by 4, then we subtract the "not c" terms.
P = (a + b + c + d)/4 . . . . maybe what you meant
4P = a + b + c + d . . . . . . multiply by 4
4P - (a +b +d) = c
c = 4P -a -b -d
when multiplying two binomials together we use the F.O.I.L. method:
First
Outer
Inner
Last
(7-3i)(2-i)
First: 7 * 2 ..... Outter: 7 * -i .... Inner: -3i * 2 ...... Last: -3i * -i
First: 14 ...... Outter= -7i ..... Inner: -6i .... Last: 3i^2
putting this together we get 14-7i-6i+2i^2
We combine like terms and end up with 2i^2-13i+14
Answer:
Converse: if 5=x then x+2=7
Inverse: if x+2 doesnt = 7 then x isnt 5
Contrapositive: if x doesnt equal five then x plus two doesnt equal seven
Step-by-step explanation:
We just did this last week :)
Answer:
0<x<1
Step-by-step explanation:
(x+3)(x−4)<−12
FOIL
x^2 -4x+3x -12 <-12
x^2 -x -12 <-12
Add 12 to each side
x^2 -x -12+12 <-12+12
x^2 -x <0
Factor out an x
x(x-1) <0
Using the zero product property
x(x-1) =0
x=0 x-1=0
x=0 x=1
Check the ranges
x<0
x(x-1) <0
- * - >0
False
0<x<1
x(x-1) <0
+ * - <0
True
x>1
x(x-1) <0
+ * + >0
False
Answer:
Step-by-step explanation:
<u>Linear Combination Of Vectors
</u>
One vector 
is a linear combination of 
and 
if there are two scalars 
such as
In our case, all the vectors are given in 
but there are only two possible components for the linear combination. This indicates that only two conditions can be used to determine both scalars, and the other condition must be satisfied once the scalars are found.
We have
We set the equation
Multiplying both scalars by the vectors
Equating each coordinate, we get
Adding the first and the third equations:
Replacing in the first equation
We must test if those values make the second equation become an identity
The second equation complies with the values of 
and 
, so the solution is
