Help for brainliest

Thirty- five out of sixty students preferred to eat their lunch at school rather going home in lunch break. Express the numbers

IceJOKER [234]

Answer:

0.583

Step-by-step explanation:

Use a caluclator

6 0

3 years ago

A rectangle has a length four more than

torisob [31]

L ≥ 5w + 4
2(L+w) ≥ 32

L+w ≥ 16

6w + 4 ≥ 16
6w ≥ 12
w ≥ 2

L ≥ 5w + 4
L ≥ 14

If L = 14 and w = 2 then the perimeter is 32.
These are the smallest dimensions that fit the criteria.

Note: If we raise the width by 1 to w = 3
then the length is at least 19. At 19 by 3 we have P = 44
Like would be appreciated!!

8 0

1 year ago

Need quick answers please

Olenka [21]

Answer:

A, E, F, D

Step-by-step explanation:

Done this before

5 0

3 years ago

PLEASE HELP!! GIVEN THE FOLLOWING TABLE OF DATA FROM A QUADRATIC EQUATION

antiseptic1488 [7]

The roots: this is when y=0, so in yours there are 2 roots. Just look at the x value when y=0 and that is your roots.

Y intercept- this is when x=0, so just look at the y value below x=0 and that is the y intercept. Note the answer will probably be in the form (0,_)

Vertex=do you see a pattern? Well the vertest would be the highest or lowest point of the quadratic equation. Your vertex would be (5,-9) because just look at x=4 and x=6, bit of the y values are -8 and when you look at x=3 and x=7 they are also the same because this is a quadratic equation.

Max or min: yours is a minimum because (5,-9) is the lowest point. Every value left and right of this are higher up the graph, so this would be a minimum.

*something that will help you see this all more clearly is if you graphed this or put it into Desmos to see the vertex etc.

7 0

3 years ago

On a snow day, Mason created two snowmen in his backyard. Snowman A was built to a height of 51 inches and Snowman B was built t

mr_godi [17]

Answer:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

t < 11 hours ... [ 0 , 11 ]

Step-by-step explanation:

Given:-

- The height of snowman A, Ao = 51 in

- The height of snowman B, Bo = 29 in

Solution:-

- The day Mason made two snowmans ( A and B ) with their respective heights ( A(t) and B(t) ) will be considered as the initial value of the following ordinary differential equation.

- To construct two first order Linear ODEs we will consider the rate of change in heights of each snowman from the following day.

- The rate of change of snowman A's height ( A ) is:

$\frac{d h_a}{dt} = -4$

- The rate of change of snowman B's height ( B ) is:

$\frac{d h_b}{dt} = -2$

Where,

t: The time in hours from the start of melting process.

- We will separate the variables and integrate both of the ODEs as follows:

$\int {} \, dA= -4 * \int {} \, dt + c\\\\A ( t ) = -4t + c$

$\int {} \, dB= -2 * \int {} \, dt + c\\\\B ( t ) = -2t + c$

- Evaluate the constant of integration ( c ) for each solution to ODE using the initial values given: A ( 0 ) = Ao = 51 in and B ( 0 ) = Bo = 29 in:

$A ( 0 ) = -4(0) + c = 51\\\\c = 51$

$B ( 0 ) = -2(0) + c = 29\\\\c = 29$

- The solution to the differential equations are as follows:

A ( t ) = -4t + 51

B ( t ) = -2t + 29

- To determine the time domain over which the snowman A height A ( t ) is greater than snowman B height B ( t ). We will set up an inequality as follows:

A ( t ) > B ( t )

-4t + 51 > -2t + 29

2t < 22

t < 11 hours

- The time domain over which snowman A' height is greater than snowman B' height is given by the following notation:

Answer: [ 0 , 11 ]

8 0

3 years ago