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3 years ago

write down the first three multiples of 15,20and 25 what generalization can you make about all multiples of 5

Mathematics

2 answers:

victus00 [196]3 years ago

6 0

All multiples of 5 end in 5 or 0.

EastWind [94]3 years ago

3 0

Multiples of 15: 30,45,60

multiples of 20: 40,60,80

multiples of 25: 50,75,100

Generalization: They will either end with the digits 0 or 5.

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400

Step-by-step explanation:

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Polly’s Pasta and Pizza Supply sells wholesale goods to local restaurants. They keep track of revenue earned from selling kitche

dimaraw [331]

Complete question :

Polly’s Pasta and Pizza Supply sells wholesale goods to local restaurants. They keep track of revenue earned from selling kitchen supplies and food products. The function K models revenue from kitchen supplies and the function F models revenue from food product sales for one year in dollars, where t represents the number of the month (1 – 12) on the last day of the month.

K(t)=15t^3–312t^2+1600t+1100

F(t)=36t3–720t2+3800t–1600

In which month was her revenue from food products the greatest? The least?

Answer:

greatest revenue = 4384

Leat revenue = 400 ; October

Step-by-step explanation:

Using the model :

Claculating the revenue from. Food sales from January through December :

F(t)=36t^3–720t^2+3800t–1600

Put t = 1, 2, 3,.. 12 for January through December

t = 1

F(1)=36(1^3) - 720(1^2) + 3800(1) - 1600 = 1516

t = 2

F(2) = 36(2^3) - 720(2^2) + 3800(2) - 1600 = 3408

Inputting the t values up to 12 to cover for January thkorugh December :

We have the data:

t1 = 1516

t2 = 3408

t3 = 4292

t4 = 4384

t5 = 3900

t6 = 3056

t7 = 2068

t8 = 1152

t9 = 514

t10 = 400

t11 = 996

t12 = 2528

Hence, greatest revenue = 4384 (month of April)

Least revenue is at t10(October) ; Lowest revenue is at t 10 = 400

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3 years ago

When expressing sets, you may write "inf" for infinity and "U" for union.

GarryVolchara [31]

Answer:

The complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

Step-by-step explanation:

The given set in interval notation is

(−5,6]

It means the set is defined as

$A=\{x|x\in R,-5$

If B is a set and U is a universal set, then complement of set B contains the elements of universal set but not the elements of set B.

Here, universal set is R, the set set of all real numbers.

$U=\{x|x\in R\}$

The complement of the given set is

$A^c=U-A$

$A^c=\{x|x\in R,-\infty$

Complement of the given set in interval notation is

$A^c=(-\infty,-5]\cup(6,\infty)$

Therefore the complement of the given set in interval notation is $(-\infty,-5]\cup(6,\infty)$ . It can we written as (-inf,5]U(6,inf).

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3 years ago

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ValentinkaMS [17]

Answer:

Some right angles

Step-by-step explanation:

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2 years ago