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adelina 88 [10]
3 years ago
15

SOVE, REDUCE TO LOWEST TEERMS SIMPLIFY IMPROPER FRACTIONSAS MIXED FRACTIONS

Mathematics
1 answer:
Margaret [11]3 years ago
3 0
I don’t see a picture
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Write the equation of the line that has undefined slope and passes through the point(-5,9)
jasenka [17]

Write the equation of the circle with center (3, 2) and radius r = 7. Use the ^ key for the exponents. Write your answer as the example: (x - 4)^2+(y+8)^2=25


6 0
3 years ago
After several shares of the company's stock were sold, a profit of $1.320 was earned. The profit was 15%
Rom4ik [11]

Answer:

$8.8

Step-by-step explanation:

Let the original price of shares be x

Profit earned = $1.320

percentage profit = 15%

∴ \frac{15x}{100} = 1.320\\15x = 132.0\\x = \frac{132}{15} \\x = 8.8

Original price of shares were = $8.8

4 0
3 years ago
A machine packs boxes at a constant rate of 2/3 of a box every 1/2 minute. What is the number of boxes per minute that the machi
larisa [96]
2/3 box  per 1/2 minute => 2(2/3) box per 2(1/2) minute 

Thus it is 4/3 box per minute
5 0
4 years ago
Which graph correctly represents 1/3y-1/2x>2 ?
Tanzania [10]
<span>Put it in the form of y =mx +b, or in this instance, y> mx +b 
move the (1/2) x to the right by adding it to both sides of the inequality 
(1/3)y>(1/2)x +2 
Multiply by 3 on both sides to get y by itself. 
y>(3/2) x +6 
This is a graph with y intercept of (0,6) and a moderate upward and to the right slope. Because it is > , the line on the graph will NOT be part of the solution. 

The easiest way to find the side of the graph that the inequality satisfies is to use (0,0) and see if it works or doesn't work. In the original equation, 0-0>2 does NOT work, so the area where the inequality works is to the up and left of the graph, which should be a dotted line to show that the inequality is greater than only. 
The point (6,-2) should work.
Test it. 6*(1/3)-(-2)*(1/2)>0 ; 2-(-1)=3, and 3>2 It does work. 
The point (6,2) should not work 
Test it. 6 *(1/3)-2(1/2)=2-1 ; 1 is NOT >2, so it does not work. 
If the graph goes through the origin, then pick a point near the graph with a small x or y.</span>
7 0
4 years ago
the formulas for area of a triangle require the length of any two sides of the triangle amd the measure of the included angle.Tr
nlexa [21]

Answer:

True

the answer to the above question is true

8 0
3 years ago
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