If you plotted the number of snacks as the x-axis, and then the total cost of the snacks on the y-axis, you would be able to graph a line and see the cost of snacks based on the number purchased. If you were going to write an equation for this, it would be y=2.25x (or y = 2 1/4 x)

In this case, as each snack is the same price, the y-values for each x would be as such: (1, 2.25) <- one snack, $2.25;

(2, 4.5)

(3, 6.75)

(4, 9)

So that is why the ordered pair of (4,9) would be a solution to this problem.

Hope that makes sense!

4 0

3 years ago

What is the x-intercept of y = 3x² + 6x + 3 ?<br> o<br> 1<br> -1<br> 3

Veronika [31]

Answer:

Therefore the x-intercept of

$y=3x^{2}+6x+3$

$x=-1$

Step-by-step explanation:

Intercepts:

The line which intersect on x-axis and y-axis are called intercepts.

There are two intercepts:

y-intercept: The line which intersect at y-axis. So when the line intersect at y-axis X coordinate is zero.

x-intercept: The line which intersect at x-axis. So when the line intersect at x-axis Y coordinate is zero.

For x-intercept of y = 3x² + 6x + 3

put y = 0

$0=3x^{2}+6x+3$

Dividing throughout by 3 we get

$0=x^{2}+2x+1$

$0=x^{2}+2\times 1\times x+1^{2}$

Which is nothing but in the identity form of (A+B)² = A² +2AB +B²

A = x

B = 1

Therefore Equation becomes

$(x+1)^{2}=0\\x+1=0\\x=-1$

Therefore the x-intercept of

$y=3x^{2}+6x+3$

$x=-1$

5 0

4 years ago