A = .33m/s^2
a=.55m/s^2
don't understand the last question
D it would grow until it had to compete for food
Answer:
The probability of producing a round and green plant from this cross is 3/16
Explanation:
This question involves two distinct genes coding for seed shape and seed colour. In the seed shape gene, allele for round seeds (R) is dominant over allele for wrinked seeds (r), while in the seed colour gene, allele for yellow seed (Y) is dominant over allele for green seeds (y).
A truebreeding plant means that the plant possesses homozygous genotype. Hence, a truebreeding pea plant with round and green seeds will have genotype: RRyy while true-breeding pea plant with wrinkled and yellow seeds will have genotype: rrYY. These two parents will produce F1 offsprings with genotype: RrYy (heterozygous).
When the F1 offsprings are self-crossed (RrYy × RrYy), the following allelic combinations of gametes will be produced by each F1 parent: RY, Ry, rY, ry
Using these gametes in a punnet square (see attached image), 16 possible F2 offsprings with a phenotypic ratio 9:3:3:1 will be produced
9- Round yellow offsprings (R_Y_)
3- Round green offsprings (R_yy)
3- Wrinkled yellow offsprings (rrY_)
1- Wrinkled green offsprings (rryy)
Genetic information is found in DNA, which is found in the nucleus. it could also be chromosomes, however.
The answer is A is you agree no problem im here to help if you disagree its ok i tried my best to help just saying