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3 years ago

How do you write (16a^6)^(3/4) in radical form?

Mathematics

1 answer:

babymother [125]3 years ago

7 0

I hope this helps you

[(2^4)^3/4][(a^6)^3/4]

(2^4.3/4)(a^6.3/4)

(2^3). (a^9/2)

2^3. a^4square root of a

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Last year the vending machine sold drinks for $1.25. This year the price is $1.50. What is the percent of markup?

Ann [662]

The percent of markup is 20%

Step-by-step explanation:

Selling price of the drink = $1.50

Cost of the drink last year = $1.25

Percent of markup = (selling price - cost) (100)/cost

Percent of markup = (1.50 - 1.25)(100) /1.25

= 0.25(100) /1.25

= 25/1.25

= 20%

The percent of markup is 20%

7 0

3 years ago

The denominators of any rational roots of a polynomial will be the factors of the ___ coefficient.

katen-ka-za [31]

The denominators of any rational roots of a polynomial will be the factors of the leading coefficient.

8 0

3 years ago

Steps to answer -3(x+4)+15=6-4x

Mariana [72]

distribute| -3x-12+15 = 6-4x
simplify| -3x+3=6-4x
solve by getting X to one side| -3=1x
answer| X=-3

8 0

3 years ago

At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o

bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, $P_0=15$

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

$P(x)=P_0(1+r)^x$

now, we can plug values

$P(x)=15(1+0.4142)^x$

$P(x)=15(1.4142)^x$

Average rate of change between 2 years and 4 years:

we can use formula

$A_1=\frac{P(4)-P(2)}{4-2}$

now, we can plug values

$A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}$

$A_1=14.99914$

Average rate of change between 4 years and 6 years:

we can use formula

$A_2=\frac{P(6)-P(4)}{6-4}$

now, we can plug values

$A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}$

$A_2=29.99770$

Average rate of change between 6 years and 8 years:

we can use formula

$A_3=\frac{P(8)-P(6)}{8-6}$

now, we can plug values

$A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}$

$A_3=59.99425$

now, we will check each options

option-A:

we can see that

$A_3-A_2=30$

So, this is FALSE

option-B:

$A_1=\frac{1}{2}A_2$

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

$A_1=\frac{1}{2}A_2$

so, this is FALSE

5 0

3 years ago

Which represents “if x=4, then y=-2”

11111nata11111 [884]

Representa una ecuacion de segundo grado. :v

6 0

3 years ago

Read 2 more answers