He will mix some 20% solution and some 70% solution to make 60% solution.
Let x = number of liters of 20% solution.
Let y = number of liters of 70% solution.
He wants to make 50 liters of 60% solution, so
x + y = 50 First Equation
The amount of acid in x amount of 20% solution is 20% of x, or 0.2x
The amount of acid in y amount of 70% solution is 70% of y, or 0.7y
The amount of acid in 50 liters of 60% solution is 60% of 50 liters, or 0.6 * 50 = 30
Now we add the amounts of acid.
0.2x + 0.7y = 30 Second Equation
x + y = 50
0.2x + 0.7y = 30
-0.2x - 0.2y = -10
0.2x + 0.7y = 30
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0.5y = 20
y = 40
x + y = 50
x + 40 = 50
x = 10
Answer: He needs 10 liters of 20% solution and 40 liters of 70% solution.
the answer is x3
11x3=33
5x3=15
multiply by 3 on all of them
mark brainliest plz
Answer:
whats the given?? what you need I don't understand
14: 1 × 14
2 × 7
56: 1 × 56
2 × 28
4 × 14
7 × 8
63: 1 × 63
3 × 21
7 × 9
GCF(14, 56, 63) = 7
Answer:
x = 76/75
Step-by-step explanation:
