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Dafna11 [192]
2 years ago
15

A playground has two poles that are used for games. the first pole is 1.83 m tall. the second pole is 2.172 m tall. how much tal

ler is the second pole than the first pole?
Mathematics
1 answer:
Sphinxa [80]2 years ago
6 0
2.172
-1.830
---------
0.342
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The vertex form:

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2x^2+12x+16=2(x^2+6x)+16=2(x^2+2(x)(3))+16\\\\=2(\underbrace{x^2+2(x)(3)+3^2}_{(*)}-3^2)+16=2((x+3)^2-9)+16\\\\=2(x+3)^2+(2)(-9)+16=2(x+3)^2-18+16\\\\=\boxed{2(x-(-3))^2-2}\to h=-3,\ k=-2

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Other method:

f(x)=ax^2+bx+c\\\\vertex:(h,\ k)\\\\h=\dfrac{-b}{2a},\ k=f(h)

We have

f(x)=2x^2+12x+16\\\\a=2,\ b=12,\ c=16

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