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Ket [755]
3 years ago
12

What is the length of the hypotenuse of a right triangle if each of the two legs is 4 units? square root of 8 units 4 units squa

re root of 32 units 8 unit?
Mathematics
2 answers:
ycow [4]3 years ago
7 0
By the Pythagoras theorem, in a right triangle with the sides being a and b,

 a² + b² = Hypotenuse²

Hypotenuse² = 4² + 4²

Hypotenuse² = 16 + 16 = 2*16

Hypotenuse = √2 * √16

Thus, hypotenuse = 4√2


USPshnik [31]3 years ago
7 0
You would use the Pythagorean theorem to solve for the hypotenuse in a right triangle. 
a^2 + b^2 = <span>c^<span>2
</span></span>c being the hypotenuse and a and b being the two legs
The square of 4 is 16, so
16+16=c^2
32=c^2
Now you have to find the square root of 32 to solve for the hypotenuse
The square root of 32 in radical form is equal to 4√2

Your answer is 4√2

<span><span><span>
</span></span></span>


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i.e. \dfrac{72}{50}=\dfrac{P^2}{P'^2}\\\\\dfrac{36}{25}=\dfrac{P^2}{P'^2}

on taking square root on both the side we get:

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Now putting the value of P in equation (1) we obtain:

\dfrac{6}{5}P'+P'=226\\\\\dfrac{6P'+5\times P'}{5}=226\\\\\dfrac{6P'+5P'}{5}=226\\\\11P'=226\times 5\\\\11P'=1130\\\\P'=\dfrac{1130}{11}=102.7272

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