The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Student A is wrong and Student B is correct.
How?
- Direction is saying to construct a line that passes through C
- The last step is enough to describe that A is wrong.
- Its saying to swing an arc(Should be line).
- On the other hand Student B has done correct
- By passing point through C and G it satisfies our required construction.
Answer:
600
Step-by-step explanation:
You would do 36,000 divided by 60 because there are 60 minutes in an hour, and it would be 600.
Answer:
clever
Step-by-step explanation:
Answer:
y=1x-6
Step-by-step explanation:
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