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4 years ago

Got stumped on the (7x^2-2) part

Mathematics

1 answer:

stira [4]4 years ago

4 0

7x²-2=0
add 2 to both sides
7x²=2
divide by 7 both sides
$x^2=\frac{2}{7}$
sqrt both sides
$x=+/-\frac{\sqrt{2}}{\sqrt{7}}$
$x=+/-\frac{\sqrt{14}}{7}$

so the possible values of x are
$x=\frac{5}{2},\frac{-\sqrt{14}}{7},\frac{\sqrt{14}}{7}$

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