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soldier1979 [14.2K]
3 years ago
13

Which ordered pairs are solutions for 4x + 2y = 14? Choose all that apply. A) (-1,9) J) (4,0) C) (1,5) D) (3, 19) E (0,2)​

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0

Answer:

A, c apply to 4x+2y=14

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a developer wants to develop 5 acres of land. Each lot in the develope is to be 1/12 of an acre. How many lots will the land dev
Nitella [24]
5/60 I think pls tell me if I was ring
6 0
3 years ago
Kyla has the number of cherries that Denise has. If Kyla has 46 cherries, how many cherries do they have altogether?​
pogonyaev

Answer:

92

Step-by-step explanation:

46 + 46 = 92

5 0
2 years ago
Read 2 more answers
Jimmy's backyard is rectangle that is 18 5/6 yards long and 10 2/5 yards wide Jim buy sod in pieces that are 1 1/3 yard long and
g100num [7]

Answer:

111 pieces of soda

Step-by-step explanation:

step 1

Find the area of the rectangular backyard

The area of the rectangular backyard is equal to

A=LW

where

L=18\frac{5}{6}\ yd=\frac{18*6+5}{6}=\frac{113}{6}\ yd

W=10\frac{2}{5}\ yd=\frac{10*5+2}{5}=\frac{52}{5}\ yd

substitute

A=(\frac{113}{6})(\frac{52}{5})

A=\frac{5,876}{30}\ yd^2

step 2

Find the area of one piece of sod

The area of the rectangular piece of sod is

A=LW

where

L=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

W=1\frac{1}{3}\ yd=\frac{1*3+1}{3}=\frac{4}{3}\ yd

substitute

A=(\frac{4}{3})^2\\\\A=\frac{16}{9}\ yd^2

step 3

Find the pieces of sod needed

To find out how many whole pieces of sod will Jim need to buy to cover his backyard, divide the area of the backyard by the area of one piece of soda

so

\frac{5,876}{30} : \frac{16}{9}=\frac{52,884}{480}=110.175

Round up

111 pieces of soda

8 0
3 years ago
Find the sum of 3.8 + (-2.9)
MakcuM [25]

Answer:

3.8 - 2.9= .9

ANSWER : .9

6 0
2 years ago
Read 2 more answers
The width of a rectangle is 6 2/3 inches. The length of the is twice it’s width. What so the perimeter of the rectangle?
Nookie1986 [14]
\text {Width = }  6\dfrac{2}{3}  \text { inches}



The length is twice its width:
\text {Length = } 2 \times 6\dfrac{2}{3} \text { inches}

Change to improper fraction:
\text {Length = }2 \times \dfrac{20}{3} \text { inches}

Combine into single fraction:
\text {Length = } \dfrac{40}{3} \text { inches}


Find Perimeter :
\text {Perimeter = Length + Length + Width + Width}

\text {Perimeter = } \dfrac{40}{3} + \dfrac{40}{3}   + \dfrac{20}{3}   + \dfrac{20}{3} = \dfrac{120}{3}  = 40 \text { inches}


\bf \text {Answer: Perimeter =  40 inches}
6 0
3 years ago
Read 2 more answers
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