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Sunny_sXe [5.5K]
2 years ago
5

Please help me with this word problem!!!

Mathematics
1 answer:
Inessa [10]2 years ago
7 0

Answer:

The number of customers needed to break even is

\simeq 6775.

Step-by-step explanation:

Rent per month = $ 7200

Rent per year, $ 7200 \times 12

                        = $ 86400 -------------(1)

Insurance per year = $ 4200 ---------(2)

Total  direct cost  for 2 servers (withoout  tax) per year,

= $ 2 \times 15 \times 8 \times 5 \times 50

= $ 60000

Total cost for helper ( without tax) per year,

= $ 4 \times 15 \times 5 \times \50

= $ 15000

Total cost for employees per year (without tax),

= $ (60000 +15000)  = $ 75000

Total cost per year for employees including tax,

$ \frac {(75000 \times (100 + 6.2 + 1.45)}{100}

= $ \frac {(75000 \times 107.65 }{100}

= $ 80737.5 -----------------------(3)

So,

total cost for running the restaurant (except food)

= (1) + (2) + (3) = $ (86400 + 4200 + 80737.5)

= $ 171337.5

Average total profit per customer,

= ( Average per customer payment - average cost of food per customer)

= $ (45.47 - 20.18)

= $ 25.29

So, total number of customer needed to break even,

= \frac {171337.5}{25.29}

\simeq   6775

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Plz help me have to turn this in today it 5:57
ruslelena [56]

Answer:

454

Step-by-step explanation:

8 0
3 years ago
Assume that in October of a particular year about 215 billion text messages were sent or received in the US, and the prediction
Julli [10]

Answer:

There will be 243 billion messages sent or received in November.

Step-by-step explanation:

Given.

Number of text messages sent or received =215 billion.

Increment on the very next month =13\%=\frac{13}{100}=0.13

Lets find what is 13\%\ of\ 215

 ⇒13\%\ of\ 215

 ⇒0.13\times 215=27.95

So we will add this value to our previous months data.

Now

Number of text messages sent in the month of November =(27.5+215)=242.95 billion.

Rounding to the nearest tenth the answer will be 243 billion.

So 243 billion text messages were sent or received in November.

5 0
3 years ago
The 100th term in 8, 13, 18,23, 28,...
Lunna [17]

Answer:

The 100th term of the sequence is 503.

Step-by-step explanation:

Given : Sequence 8, 13, 18,23, 28,...

To find : The 100th term in the sequence ?

Solution :

Sequence 8, 13, 18,23, 28,... is the arithmetic sequence

Where, First term is a=8

The common difference is d=13-8=5

The nth term of the sequence is given by a_n=a+(n-1)d

The 100th term is given by,

a_{100}=8+(100-1)5

a_{100}=8+(99)5

a_{100}=8+495

a_{100}=503

The 100th term of the sequence is 503.

3 0
3 years ago
The difference of two numbers is 8. When twice the first number is added to three times the second number, the result is 51. Wha
Naya [18.7K]
The answer is b. 15 & 7
8 0
2 years ago
The difference of two numbers is 3. Their sum is - 24. Find the numbers.
Katarina [22]

Answer:

y = -13.5

x = -10.5

Step-by-step explanation:

Hi there!

Let the two numbers be equal to <em>x</em> and <em>y</em>.

The difference of two numbers is 3 ⇒ x - y = 3

Their sum is - 24 ⇒ x + y = -24

Solve using elimination:

x - y = 3

x + y = -24

Add the two equations:

x + x - y + y = 3 - 24

2x = -21

x = -10.5

Solve for y:

-10.5 - y = 3

- y = 3 + 10.5

y = -13.5

I hope this helps!

4 0
3 years ago
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