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BARSIC [14]
3 years ago
8

Which functions have the same rate of change?

Mathematics
1 answer:
Anestetic [448]3 years ago
6 0

Answer:

Option 3

Step-by-step explanation:

All equations are in slope-intercept form. y=mx+b

The 'm' is the slope.

The 'b' is the y-intercept.

The slope is also known as the rate of change. So, we would have to look at what replaces 'm' and select two equations that have the same rate of change.

<em>Let's look over the equations:</em>

<h3>Equation A:</h3>

y=0.3x-6

In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.

<h3>Equation B:</h3>

y=3x-8

In this equation, 3 replaces 'm', so the rate of change for this equation is 3.

<h3>Equation C:</h3><h3>y=0.3x+4</h3>

In this equation, 0.3 replaces 'm', so the rate of change for this equation is 0.3.

<h3>Equation D:</h3><h3>y=0.03x+1</h3>

In this equation, 0.03 replaces 'm', so the rate of change for this equation is 0.03.

Equation C and equation A have 0.3 as the slope. Since the question asks for two equations that have the same rate of change, the answer would be Equations A and C, or Option 3.

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Answer:

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Step-by-step explanation:

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(-2,infinite]

negative two and the infinite symbol
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Which graph represents a proportional relationship? On a coordinate plane, a straight line crosses the y-axis at (0, 0). On a co
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3 years ago
Michael, Leo and JuWoong collect stamps. The ratio of the number of Michael's stamps to JuWoong's stamps is 2:7. The number of J
Alisiya [41]

Answer:

990

Step-by-step explanation:

M/J = 2/7

J = 3/4 L

L = M + 396

7M = 2J

J = 3.5M

3.5M = 3/4 L

L = 4/3(3.5M)

L = 14/3 M

14/3 M = M + 396

11/3 M = 396

M = 3/11 × 396

M = 108

L = M + 396

L = 108 + 396

L = 504

J = 3/4 L

J = 3/4 × 504

J = 378

M + L + J = 108 + 504 + 378 = 990

4 0
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The number of adults who attend a county fair (measured in hundreds of people) is represented by the function a(d)=−0.3d2+4d+9 ,
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Given is the function for number of adults who visit fair at day 'd' after its opening, a(d) = −0.3d² + 4d + 9.

Given is the function for number of children who visit fair at day 'd' after its opening, c(d) = −0.2d² + 5d + 11.  

Any function f(d) to find excess of children more than adults can be written as follows :-  

f(d) = c(d) - a(d).

⇒ f(d) = (−0.2d² + 5d + 11) - (−0.3d² + 4d + 9)

⇒ f(d) = -0.2d² + 0.3d² + 5d - 4d + 11 - 9

⇒ f(d) = 0.1d² + d + 2

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