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3 years ago

Using the letters in the word INNOVATIVE, find the number of permutations that can be formed using 3 letters at a time.

Mathematics

2 answers:

adell [148]3 years ago

8 0

D is the correct answer

snow_lady [41]3 years ago

6 0

the number of permutations that can be formed using 3 letters at a time is D.720

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Which recursive formula is represented by the sequence shown on the table?

Tresset [83]

Answer:

C) aₙ = aₙ₋₁ + 200

Step-by-step explanation:

Each term is 200 more than the previous term. So:

aₙ = aₙ₋₁ + 200

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3 years ago

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3 years ago

In Aunt Peggy’s backyard there are cows and chickens. There are 20 more chickens than cows. The total number of legs is 130. How

finlep [7]

Answer:

There's 15 cows and 35 chickens.

Step-by-step explanation:

Take 20 and multiply it by 2. The answer is 40. Then subtract 40 from 130. The answer will be 90. The cow has double the amount of legs than the chicken, so the cow is equivalent to 2 chicken. Divide 90 by 3. The answer is 30. Then divide 30 by 2 the answer is 15. Add 15 and 20 and the answer is 35 chickens. Divide 30 by 2 and the answer is 15.

You will get 35 chicken and 15 cows as your answer. Happy Election Night, and I hope this helps! ;)

5 0

3 years ago

This recipe makes 30 shortbread fingers.

siniylev [52]

Answer:

24 g butter

12 g sugar

36 g flour

Step-by-step explanation:

The recipe makes 30 shortbread fingers.

She wants to make 6 fingers.

6/30 = 1/5

She wants to make 1/5 of the recipe, so she needs 1/5 of each ingredient's amount.

Divide each amount by 5.

Recipe:

Makes 30 30/5 = 6 Makes 6

120 g butter 120/5 = 24 24 g butter

60 g sugar 60/5 = 12 12 g sugar

180 g flour 180/5 = 36 36 g flour

8 0

3 years ago

A random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample stand

Tpy6a [65]

Answer:

We conclude that the population mean is different from 10.5.

Step-by-step explanation:

We are given that a random sample of 16 values is drawn from a mound-shaped and symmetric distribution. The sample mean is 11 and the sample standard deviation is 2.

We have to test the claim that the population mean is 10.5.

Let, NULL HYPOTHESIS, $H_0$ : $\mu$ = 10.5 {means that the population mean is 10.5}

ALTERNATE HYPOTHESIS, $H_a$ : $\mu \neq$ 10.5 {means that the population mean is different from 10.5}

The test statistics that will be used here is One-sample t-test;

T.S. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean = 11

s = sample standard deviation = 2

$\mu$ = population mean

n = sample of values = 16

So, test statistics = $\frac{11-10.5}{\frac{2}{\sqrt{16} } }$ ~ $t_1_5$

= 1

Now, at 0.05 significance level, t table gives a critical value of 2.131 at 15 degree of freedom. Since our test statistics is way less than the critical value of t so we have insufficient evidence to reject null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the population mean is different from 10.5.

6 0

4 years ago