I need help answering

Mathematics

2 answers:

Ratling [72]3 years ago

8 0

$\frac{1 }{2} (7)(4) \\ \frac{1}{2} \times 28 \\ 14$

Arte-miy333 [17]3 years ago

7 0

1/2(7)(4)

= 14 cm

Hope this help

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Please help with this question.

Rzqust [24]

(cos Ф -cos Ф)² + (cos Ф + cos Ф)²

Firstly: (cos Ф -cos Ф)² = 0² = 0

Secondly :(cos Ф + cos Ф)² = (2cos Ф)². = 4. (cos Ф)² = 4cos² Ф

Mind you when you raise a cosine (or sin or tan...) to the n power, the n power should affect the cosine only and NOT the angle Ф

4 0

3 years ago

Two trains begin in Milford and end in Pinkerton, which is 300 miles away. Train A leaves Milford at 10:00 a.M. And travels at a

cluponka [151]

Answer:

B. Train B

Step-by-step explanation:

We are told that Milford and Pinkerton is 300 miles away.

Train A leaves Milford at 10:00 am. There are 3 hours between 10:00 am to 1:00 pm. So let us find distance traveled by train A in 3 hours.

$\text{Distance}=\text{Speed*Time}$

$\text{Distance traveled by train A}=90\frac{\text{ miles}}{\text{ hour}}\times 3\text{ hours}$

$\text{Distance traveled by train A}=90\times 3{\text{ miles}$

$\text{Distance traveled by train A}=270{\text{ miles}$

Since train A will cover 270 miles in 3 hours and distance between Milford and Pinkerton is 300 miles, therefore, train A will not arrive Pinkerton before 1:00 pm.

Since there are 5 hours between 8:00 am to 1:00 pm, so let us find distance traveled by train B in 5 hours.

$\text{Distance traveled by train B}=70\frac{\text{ miles}}{\text{ hour}}\times 5\text{ hours}$