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3 years ago

11

tony owns a special pet store that sell only snake and elephant. currently, he has a total of 11 snake and elephant in stock. Th

e animals that he has he has in stock have a total of 12 legs. how many of his animal are snake

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:

There are 8 snakes.

Step-by-step explanation:

12/4=3

11-3=8

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Is 10/9 closets to 0, 1/2 ,or 1

VARVARA [1.3K]

1 because 10/9= 1 1/10
which is closer to 1

3 0

3 years ago

Read 2 more answers

‘write an equation of the line that passes through each pair of points’ (1,2) and (4,8)

Levart [38]

<u><em>Hi there! </em></u>

Step-by-step explanation:

$Slope=\frac{Y_2-Y_1}{X_2-X_1}=\frac{RISE}{RUN}$

$\frac{8-2}{4-1}=\frac{6}{3}=2$

<em><u>So therefore, the slope is 2.</u></em>

<em><u>Final answer is 2.</u></em>

<em><u>*The answer must have a positive sign.*</u></em>

I hope this helps you!

Have a nice day! :)

-Charlie

:D

8 0

3 years ago

Zappos is an online retailer based in Nevada and employs 1,300 employees. One of their competitors, Amazon, would like to test t

Amanda [17]

Answer:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

$df = n-1= 22-1=21$

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

Step-by-step explanation:

Data given

$\bar X=33.9$ represent the sample mean

$s=4.1$ represent the sample standard deviation

$n=22$ sample size

$\mu_o =26$ represent the value that we want to test

$\alpha=0.025$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

System of hypothesis

We need to conduct a hypothesis in order to check if the true mean is less than 36 years old, the system of hypothesis would be:

Null hypothesis: $\mu \geq 36$

Alternative hypothesis: $\mu < 36$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing we got:

$t=\frac{33.9-36}{\frac{4.1}{\sqrt{22}}}=-2.402$

Now we can calculate the critical value but first we need to find the degreed of freedom:

$df = n-1= 22-1=21$

So we need to find a critical value in the t distribution with df =21 who accumulates 0.025 of the area in the left and we got:

$t_{\alpha/2}= -2.08$

Since the calculated values is lower than the critical value we have enough evidence to reject the null hypothesis at the significance level of 2.5% and we can say that the true mean is lower than 36 years old

3 0

3 years ago

Ber [7]

Answer:

The expressions for the payment made to Mary are,

(Monday) 90 = 15m + b

(Tuesday) 62 = 8m + b

where m and b are the fee per student and the base fee, respectively. Solving for m and b, the values are 4 and 30.

The equation that represents Mary's earning is

y = 4x + 30

For 20 students,

y = 4(20) + 30 = 110

For Lisa's earnings,

y = 8x + 15

Substituting 20,

y =8(20) + 15 = 175

Thus, Lisa would earn more than Mary by $65.

(Btw this is not my work, I got it from someone else on brainly and wanted to help lol)

7 0

3 years ago

Mrs. Mobley can jog 3 miles in 27 minutes. How many miles can she jog in 81 minutes?

zalisa [80]

Answer:

9 miles

Step-by-step explanation:

You need to get 27 minutes to 81 minutes so you multiply 27 by 3, and that is 81, so you simply multiply 3 by 3 and get 9! Hope this helps! ;)

(27 x 3) = 81

(3 x3) = 9

3 0

3 years ago