Answer: A
Step-by-step explanation
2.167x10^4 = 21,670
= 9,978
1.1x10^6
1100,000
= 56,344,000
2.468×10^5 = 246,800
Answer:
2.4 cm.
Step-by-step explanation:
1. Find Midpoint of segment AB which is 10/2 = 5.
2. Find Midpoint of segment BC which is 5.2/2 = 2.6.
3. Subtract both midpoints 5 - 2.6 = 2.4.
That's pretty much it, Hope it helps!
Answer:
12.16 it's a continues answer tho
Answer:
- see the attachment
- (x, y) = (1, 1)
Step-by-step explanation:
1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...
y = 2x+3
which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.
__
2. You can add the two equations to eliminate y:
(3x +y) +(x -y) = (4) +(0)
4x = 4
x = 1
1 - y = 0 . . . . substitute into the the second equation
1 = y . . . . . . . add y
The solution is (x, y) = (1, 1).
Let P be Brandon's starting point and Q be the point directly across the river from P.
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>
<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>
<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>
<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>
<span>3x = sqrt(2500 + x^2) ----> </span>
<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>
<span>which is about 17.7 m downstream from Q. </span>
<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>
<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>
<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
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</span><span>mind blown</span>
