Question

What is the following profuct? ( sqrt 14 - sqrt 3) ( sqrt 12 + sqrt 7)

Answer 1

Answer:$2\sqrt{42}+7\sqrt{2}-6-\sqrt{21}$

Step-by-step explanation:

Given

$\left ( \sqrt{14}-\sqrt{3}\right )\left ( \sqrt{12}-\sqrt{7}\right )$

using distributive property

$\sqrt{14\times 12}+\sqrt{14\times 7}-\sqrt{3\times 12}-\sqrt{3\times 7}$

$\sqrt{4\times 2\times 3\times 7}-\sqrt{7\times 7\times 2}-\sqrt{36}-\sqrt{3\times 7}$

$2\sqrt{42}+7\sqrt{2}-6-\sqrt{21}$

Answer 2

Using the distributive law:-

this =  sqrt 14 sqrt 12 + sqrt 14 sqrt 7  - sqrt 3 sqrt 12 - sqrt 3 sqrt 7

= sqrt1 68 + sqrt 91 - sqrt 36 - sqrt 21

= sqrt 168 + sqrt 91 - sqrt21 - 6