1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
goldfiish [28.3K]
3 years ago
10

Show proooof, pls!!!!!!

Mathematics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

\boxed{\text{38.5 units}^{2}}

Step-by-step explanation:

The polygon is a trapezoid on its side.

The formula for the area of a trapezoid is  

A = ½(a + b)h,

where a and b are the lengths of the parallel sides and h is the distance between them.

AD = a = 2 – (-2) = 2 + 2 = 4 units

BC = b = 2 – (-5) = 2 + 5 = 7 units

AB = h = 3 – (-4) = 3 + 4 = 7 units

A = ½(4 + 7) × 7 = ½ × 11 × 7 = 38.5 units²

\boxed{\text{A = 38.5 units}^{2}}

elena-14-01-66 [18.8K]3 years ago
6 0

answer for this question is 3.85 units squared

You might be interested in
Number 1d please help me analytical geometry
lesantik [10]
For a) is just the distance formula

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ x}}\quad ,&{{ 1}})\quad 
%  (c,d)
B&({{ -4}}\quad ,&{{ 1}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\sqrt{8} = \sqrt{({{ -4}}-{{ x}})^2 + (1-1)^2}
\end{array}
-----------------------------------------------------------------------------------------
for b)  is also the distance formula, just different coordinates and distance

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -7}}\quad ,&{{ y}})\quad 
%  (c,d)
B&({{ -3}}\quad ,&{{ 4}})
\end{array}\ \ 
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
4\sqrt{2} = \sqrt{(-3-(-7))^2+(4-y)^2}
\end{array}
--------------------------------------------------------------------------
for c)  well... we know AB = BC.... we do have the coordinates for A and B
so... find the distance for AB, that is \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ -3}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 5}}\quad ,&{{ -2}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=\boxed{?}

\end{array}

now.. whatever that is, is  = BC, so  the distance for BC is

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
B&({{ 5}}\quad ,&{{ -2}})\quad 
%  (c,d)
C&({{ -13}}\quad ,&{{ y}})
\end{array}\qquad 
%  distance value
\begin{array}{llll}

d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\
d=BC\\\\
BC=\boxed{?}

\end{array}

so... whatever distance you get for AB, set it equals to BC, BC will be in "y-terms" since the C point has a variable in its ordered points

so.. .solve AB = BC for "y"
------------------------------------------------------------------------------------

now d)   we know M and N are equidistant to P, that simply means that P is the midpoint of the segment MN

so use the midpoint formula

\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
M&({{-2}}\quad ,&{{ 1}})\quad 
%  (c,d)
N&({{ x}}\quad ,&{{ 1}})
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=P
\\\\\\


\bf \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)=(1,4)\implies 
\begin{cases}
\cfrac{{{ x_2}} + {{ x_1}}}{2}=1\leftarrow \textit{solve for "x"}\\\\
\cfrac{{{ y_2}} + {{ y_1}}}{2}=4
\end{cases}

now, for d), you can also just use the distance formula, find the distance for MP, then since MP = PN, find the distance for PN in x-terms and then set it to equal to MP and solve for "x"


7 0
3 years ago
Chloe is installing new windows in her house and needs to determine the amount of sealant she will need around the outside edge
Alexus [3.1K]
36 inches is the correct answer 

I Hope This Helps
3 0
3 years ago
Read 2 more answers
3/4 mile each day for 8 days how far did I walk
Bingel [31]

Answer:

6 miles

Step-by-step explanation:

Since you walked 3/4 miles in 1 day then in 8 days you walked...

3/4*8=3*2=6 miles

4 0
3 years ago
Read 2 more answers
Cindy claims that 4^x/12^x=1/3
pav-90 [236]
A whole number that would support Cindys claim would be 2 because if u do the ,math it would be 8/24 which would be .333 repeating which is simplify to 1/3 and i do not know a number that would not work
4 0
3 years ago
Help me on this please.
frosja888 [35]


it’s system of substitutions ?
so try

a = 2
b = 5
8 0
2 years ago
Other questions:
  • Nando has 4 goldfish. Jill has 3 goldfish. Cooper has 2 times as many goldfish as Nando and Jill combined. Write an equation tha
    8·2 answers
  • Rolling a 5 on a fair number cube?
    9·1 answer
  • What is the slope of the line that passes through the points (−4,8) and (-14, 8) ? answer inn simplest form
    14·1 answer
  • How many equal pieces of rope if i have 63 meters and need it in nine equal pieces
    12·1 answer
  • Helpppppp 10points some plz help
    5·1 answer
  • Can someone help me with this problem?
    5·1 answer
  • An aeroplane covers a distance of 1500km in a certain time at a certain speed.After increasing the speed by 100km/hr, it covers
    6·2 answers
  • BRAINIEST AND 10 POINTS <br> IREADY TEST
    11·1 answer
  • Cheat on a test with me ;) LOL
    5·2 answers
  • Sami cuts out a rectangle that has a perimeter of 48 inches and a length of 13 inches.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!