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goldfiish [28.3K]
3 years ago
10

Show proooof, pls!!!!!!

Mathematics
2 answers:
castortr0y [4]3 years ago
7 0

Answer:

\boxed{\text{38.5 units}^{2}}

Step-by-step explanation:

The polygon is a trapezoid on its side.

The formula for the area of a trapezoid is  

A = ½(a + b)h,

where a and b are the lengths of the parallel sides and h is the distance between them.

AD = a = 2 – (-2) = 2 + 2 = 4 units

BC = b = 2 – (-5) = 2 + 5 = 7 units

AB = h = 3 – (-4) = 3 + 4 = 7 units

A = ½(4 + 7) × 7 = ½ × 11 × 7 = 38.5 units²

\boxed{\text{A = 38.5 units}^{2}}

elena-14-01-66 [18.8K]3 years ago
6 0

answer for this question is 3.85 units squared

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Xavier, Yolanda and Sara shared some money. Yolanda received 40% more money than Xavier, and Zara received 60% of Yolanda's shar
leonid [27]

Answer:

Step-by-step explanation:

Xavier, Yolanda and Zara shared some money.

Let x represent Xavier's share

Let y represent Yolanda's share

Let z represent Zara's share.

Yolanda received 40% more money than Xavier. This means that

y = x + 40/100×x = x + 0.4x = 1.4x

Zara received 60% of Yolanda's share. This means that

z = 60/100× 1.4 = 0.6×1.4 = 0.84x

. If Zara received $1,176, then,

0.84x = 1176

x = 1176/0.84 = 1400

y = 1.4 × 1400 = $1960

z = 0.84 × 1400 = $1176

The sum of the money is

1400 + 1960 + 1176 = $4536

6 0
3 years ago
Granola Crunch cereal is packaged in 1 pound boxes. Susan Torres, a quality control analyst who works for the manufacturer of th
sineoko [7]

Answer:

z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162    

p_v =2*P(z>3.162)=0.0016    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.

Step-by-step explanation:

Data given and notation    

\bar X=1.02 represent the sample mean

\sigma=0.04 represent the population standard deviation    

n=40 sample size    

\mu_o =1 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.    

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the true mean is equal to 1 pound or no :    

Null hypothesis:\mu =1    

Alternative hypothesis:\mu \neq 1    

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic    

We can replace in formula (1) the info given like this:    

z=\frac{1.02-1}{\frac{0.04}{\sqrt{40}}}=3.162    

P-value    

Since is a two-sided test the p value would be:    

p_v =2*P(z>3.162)=0.0016    

Conclusion    

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to to reject the null hypothesis, so we can conclude that the true mean is different from 1 pound at 5% of signficance.    

5 0
3 years ago
Do these pairs of values (x and y) represent two quantities that are proportional? PLEASE HELP
Brilliant_brown [7]
Yes it does. If you divide each of the y values by their corresponding x values you will see a pattern. If this pattern is the same number over and over, it is the same ratio.
3 0
3 years ago
The airline tickets to Jamaica that you want to buy just went on sale. They were originally $1100 and the sale price is $600. Wh
V125BC [204]

Step-by-step explanation:

100% = $1100

1% = 100%/100 = 1100/100 = 11

how many % are $600 ?

that is how often does 1% fit into $600 ?

600 / 11 = 54.545454... %

rounded that means 55%.

so, the making down percentage is then the difference

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8 0
2 years ago
If the ratio of the corresponding side lengths of two similar polygons is 6:11 what is the ratio of their areas?
ollegr [7]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\


\bf -------------------------------\\\\
6:11\qquad \cfrac{6}{11}\qquad \stackrel{sides'~ratio}{\cfrac{6}{11}}\qquad \qquad \stackrel{areas'~ratio}{\cfrac{6^2}{11^2}}\implies \cfrac{36}{121}
7 0
3 years ago
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