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4 years ago

Cos 105sin 15 how do you show work to solve this

1 answer:

8 0

One very simple way is to put it in a Ti-84 calculator which shows that cos(105) is -0.2409590492 and sin(15) as 0.6502978402 which you can find online.

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Cody made 3/4 of a kilogram of trail mix. If he puts 3/8 of a kilogram into each bag, how many bags can Cody fill?

cluponka [151]

Answer:

Step-by-step explanation:

Considering x the number of bags he can fill:

x $\frac{3}{8} x = \frac{3}{4} \\x = \frac{3}{4} X \frac{8}{3}\\ x =\frac{24}{12}\\ x = 2$

I hope I made myself clear.

8 0

2 years ago

Please answer the following:

balandron [24]

Answer: The first two recipes will taste the same. The third one will taste different.

Step-by-step explanation: The first two recipes have the same ratio of 2 orange juice to 3 pineapple juice.

8 0

3 years ago

Read 2 more answers

See image for details on question

exis [7]

Answer:

x +3

Step-by-step explanation:

You can solve this by factoring.

The numbers have to add to 10 and multiply to 21.

The first numbers that should come to mind are 7 and 3

(x+3)(x+7)

x+3 is the shorter side and there you go :)

7 0

3 years ago

points C,D, and E are collinear on CE, and CD:DE = 3/5. C is located at (1,8), D is located at (4,5), and E is located at (x,y).

kap26 [50]

Answer:

The point E is located at (9,0)

x=9, y=0

Step-by-step explanation:

we have that

Points C,D, and E are collinear on CE

Point D is between point C and point E

we know that

$CE=CD+DE$ -----> equation A (by addition segment postulate)

$\frac{CD}{DE}=\frac{3}{5}$

$CD=\frac{3}{5}DE$ ------> equation B

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance CD 

we have

C(1,8), D(4,5)

substitute in the formula

$CD=\sqrt{(5-8)^{2}+(4-1)^{2}}$

$CD=\sqrt{(-3)^{2}+(3)^{2}}$

$CD=\sqrt{18}\ units$

Find the distance DE

substitute the value of CD in the equation B and solve for DE

$\sqrt{18}=\frac{3}{5}DE$

$DE=\frac{5\sqrt{18}}{3}\ units$

Find the distance CE

$CE=CD+DE$

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

$CD=\sqrt{18}\ units$

substitute the values in the equation A

$CE=\sqrt{18}+\frac{5\sqrt{18}}{3}$

$CE=\frac{8\sqrt{18}}{3}$

Applying the formula of distance CE

we have

$CE=\frac{8\sqrt{18}}{3}$

C(1,8), E(x,y)

substitute in the formula of distance

$\frac{8\sqrt{18}}{3}=\sqrt{(y-8)^{2}+(x-1)^{2}}$

squared both sides

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

Applying the formula of distance DE

we have

$DE=\frac{5\sqrt{18}}{3}\ units$

D(4,5), E(x,y)

substitute in the formula of distance

$\frac{5\sqrt{18}}{3}=\sqrt{(y-5)^{2}+(x-4)^{2}}$

squared both sides

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

we have the system

$128=(y-8)^{2}+(x-1)^{2}$ -----> equation C

$50=(y-5)^{2}+(x-4)^{2}$ -----> equation D

Solve the system by graphing

The intersection point both graphs is the solution of the system

The solution is the point (9,0)

therefore

The point E is located at (9,0)

see the attached figure to better understand the problem

6 0

3 years ago

Find algebraically in RxR using substituting method the S.S. of the two equations:

Art [367]

Answer:

x=3 y=1

Step-by-step explanation:

x+y=4

y=-x+4

plug in the y

2x-(-x+4)=5

2x+x-4=5

3x=9

x=3

plug in x=3 into first equation to find y

y=-(3)+4

y=-3+4

y=1

8 0

3 years ago

Read 2 more answers