Answer:
11) 662
12) 24
Step-by-step explanation:
2 (11x11x11 - 1000) = 2(1331-1000)
= 2(331) = 662
1/8 (256 - 64)
= 1/8 (192)
= 198/8 = 24
Answer:
0.75x
Step-by-step explanation:
Theres not much to show. It says that you buy x bags of chips for $0.75. So how I got 0.75x is because you have to multiply 0.75 x times to get your answer,but here they just want you to write an equation with out solving it.
Answer:
By the looks of it you got them all, correct!
Your handwriting is quite nice by the way!
Step-by-step explanation:
Have a good day!
The school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².
<h3>What is a quadratic equation?</h3>
Any equation of the form
where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.
As we know, the formula for the roots of the quadratic equation is given by:
![\rm x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Crm%20x%20%3D%20%5Cdfrac%7B-b%20%5Cpm%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
We have:
A school bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².
From the second equation of motion:
![\rm s = u + \dfrac{1}{2}at^2](https://tex.z-dn.net/?f=%5Crm%20s%20%3D%20u%20%2B%20%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
We have given:
s = 95.1 m
u = 26.8 m/s
a = 4.73 m/s²
![\rm 95.1 = 26.8 + \dfrac{1}{2}(4.73)t^2](https://tex.z-dn.net/?f=%5Crm%2095.1%20%3D%2026.8%20%2B%20%5Cdfrac%7B1%7D%7B2%7D%284.73%29t%5E2)
The above equation is a quadratic equation:
After simplification:
![\rm \dfrac{4.73}{2}t^2=68.3](https://tex.z-dn.net/?f=%5Crm%20%5Cdfrac%7B4.73%7D%7B2%7Dt%5E2%3D68.3)
![\rm t^2=28.879](https://tex.z-dn.net/?f=%5Crm%20t%5E2%3D28.879)
t = 5.373 seconds ≈ 5.34 seconds
Thus, the school bus will take 5.34 seconds to travel 95.1 m if the bus is moving 26.8 m/s on flat ground when it begins to accelerate at 4.73 m/s².
Learn more about quadratic equations here:
brainly.com/question/2263981
#SPJ1
Answer:
![(x+y)(y-5)](https://tex.z-dn.net/?f=%28x%2By%29%28y-5%29)
Step-by-step explanation:
![x(y-5)-y(5-y)\\\\x(y-5)-y[-(y-5)]\\\\x(y-5)+y(y-5)\\\\Take\ (y-5)\ common\\\\(x+y)(y-5)](https://tex.z-dn.net/?f=x%28y-5%29-y%285-y%29%5C%5C%5C%5Cx%28y-5%29-y%5B-%28y-5%29%5D%5C%5C%5C%5Cx%28y-5%29%2By%28y-5%29%5C%5C%5C%5CTake%5C%20%28y-5%29%5C%20common%5C%5C%5C%5C%28x%2By%29%28y-5%29)