All categories

3 years ago

What is the numbers (3, 5) and (6, 9) placed on a graph

Mathematics

1 answer:

labwork [276]3 years ago

4 0

When we want to draw a point on the graph we need to have a value of x and y i.e (x,y)

Step-by-step explanation:

We need to place the numbers (3,5) and (6,9) on graph.

When we want to draw a point on the graph we need to have a value of x and y i.e (x,y)

So, for given point (3,5) the value of x = 3 and y=5

For placing it on graph choose 3 on x-axis and 5 on y-axis, the place where both points meet is the point (3,5)

Similarly for point (6,9) the value of x = 6 and y=9

For placing it on graph choose 6 on x-axis and 9 on y-axis, the place where both points meet is the point (6,9)

The points place on graph are shown in figure attached.

Keywords: graph the points

Learn more about graph the points at:

#learnwithBrainly

You might be interested in

Which is a true statement about the diagram?

Orlov [11]

Answer:b

Step-by-step explanation:

4 0

3 years ago

Help me please thanks

Zarrin [17]

FORMULA:

Pythagorean property —: h² = b² + p², where h = hypotenuse, b = base, p = perpendicular.

ANSWER:

By pythagorean property,

x² = 25² + 100²
x² = 625 + 10000
x² = 10625
x = √10625
x = 103 cm rounded.

Hence, the length of x is 103 cm.

8 0

3 years ago

An investor bought 500 shares of stock, some at $6.25 per share and some at $6.50 per share. If the total cost was $3218.75, how

Rudiy27

Step-by-step explanation:

x = amount of shares for $6.25

y = account of shares for $6.50

x + y = 500

x×6.25 + y×6.5 = 3218.75

x = 500 - y

(500 - y)×6.25 + y×6.5 = 3218.75

3125 - y×6.25 + y×6.5 = 3218.75

0.25×y = 93.75

y = 375

x = 500 - 375 = 125

so, he bought

375 shares of $6.50

125 shares of $6.25

4 0

3 years ago

Please help please please

Liula [17]

Length of shorter piece is 13 ft

Length of longer piece is 61 - 13 => 48 ft

5 0

4 years ago

How much money would you have in your savings balance after 3 years if you initially invested $900 and had an interest rate of 1

denis-greek [22]

assuming simple interest

$~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$900\\ r=rate\to 1\%\to \frac{1}{100}\dotfill &0.01\\ t=years\dotfill &3 \end{cases} \\\\\\ A=900[1+(0.01)(3)]\implies A=900(1.03)\implies A=927$

8 0

2 years ago