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3 years ago

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In circle O, diameter AB has been drawn. Locate point C anywhere between A and B (on either side of the diameter). Draw in AC an

d BC . What type of triangle is ACB ? Explain.

1 answer:

-Dominant- [34]3 years ago

8 0

Answer:

Right Triangle.

Step-by-step explanation:

Given AB is a diameter of a circle O.

Point C is located on the circle's circumference as shown in the attached diagram.

$\angle AOB=180^\circ$

Theorem: The angle at the centre is twice the angle at the circumference.

The angle formed at centre O by arc AB is $\angle AOB$

The angle formed at the circumference at point C by arc AB is $\angle ACB$

By the theorem above:

$\angle AOB=2*\angle ACB\\180^\circ=2*\angle ACB\\\angle ACB=90^\circ$

Therefore, Triangle ACB is a Right Triangle with the right angle at C.

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Solve the equation <br> (If possible please show work)

Kryger [21]

Answer:

x = 0

Step-by-step explanation:

First, distribute the -4 to the parentheses:

-4 + 3x = 2x - 4(1 - 3x)

-4 + 3x = 2x - 4 + 12x

Then, add like terms:

-4 + 3x = 14x - 4

Solve for x:

3x = 14x

0 = 11x

0 = x

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3 years ago

Read 2 more answers

Suppose that you play the game with three different friends separately with the following results: Friend A chose scissors 100 t

Yanka [14]

Answer:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of scissors selected for each friend

$\hat p=\frac{X}{n}$ estimated proportion of scissors selected for each friend

$p_o=\frac{1}{3}=0.333$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the proportion that the friend will pick scissors is less than 1/3 or 0.333, the system of hypothesis would be:

Null hypothesis: $p\geq 0.333$

Alternative hypothesis: $p < 0.333$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

Friend A

$\hat p_A= \frac{100}{400}=0.25$

$z=\frac{0.25 -0.333}{\sqrt{\frac{0.333(1-0.333)}{400}}}\approx -3.47$

Friend B

$\hat p_B= \frac{20}{120}=0.167$

$z=\frac{0.167 -0.333}{\sqrt{\frac{0.333(1-0.333)}{120}}}\approx -3.80$

Friend C

$\hat p_C= \frac{65}{300}=0.217$

$z=\frac{0.217-0.333}{\sqrt{\frac{0.333(1-0.333)}{300}}}\approx -4.17$

So then the best solution for this case would be:

-3.47 (100 out of 400; 25%), -3.80 (20 out of 120; 16.7%), -4.17 (65 out of 300; 21.7%)

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4 years ago

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Answer:14x+4

Step-by-step explanation:

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andrew11 [14]

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\begin{array}{llll}
\textit{\underline{y} varies directly with \underline{x}}\\
\textit{and inversely with \underline{z}}
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\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
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3 years ago

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Delicious77 [7]

Answer:

see below

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