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Phantasy [73]
1 year ago
13

Solve for x.Question options:A) 11 B) 13 C) 12 D) 10

Mathematics
1 answer:
babymother [125]1 year ago
7 0

Line YZ is the midsegment of triangle QRS because it connects the midpoints of lines QR and RS. We would solve for x by appying the midsegment theorem which states that the midsegment is half the length of the third side or base. This means that

YZ = 1/2(QS)

x + 2 = 1/2 * (3x - 8)

2(x + 2) = 3x - 8

By opening the parenthesis, we have

2x + 4 = 3x - 8

Collecting like terms, we have

3x - 2x = 4 + 8

x = 12

Option C is correct

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3 years ago
-6(a+8) simple expression
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4 0
4 years ago
What is the least natural number which when divided by 3,5,6,8,10 and 12 leaves in each case remainder 2 but when divided by 13
bazaltina [42]

Answer:

962

Step-by-step explanation:

MMM for step by step its kinda just plug and check

962/3 = 320 R2

962/6 = 160 R2

962/8 = 120 R2

962/10 = 96 R2

962/12 = 80 R2

and finally 962/13 = 74

4 0
2 years ago
The number N = 100+100^2+100^3 + ... +100^n . Find the least possible value of n such that the number N is divisible by 11.
soldier1979 [14.2K]

It's a big alphabet, why confuse us with N and n?

Anyway, this one is a bit easier than it looks.  We're going to look at it mod 11, meaning we're only interested in the remainders when we divide by 11.  The nice thing about multiplication and addition is if we're going to take the remainder at the end, we can also take the remainders at the beginning and along the way and get the same answer, with smaller numbers.

That all sounds very complicated.  It's easier explained.

100 =9*11 +1 so has remainder 1 when divided by 11.  So if we multiply by 100 that's not going to change the remainder when we divided by 11; it's like multiplying by 1.

So 100, 100^2, 100^3, etc all have remainder 1 when divided by 11.  So we need to add up 11 of them to get a number that's divisible by 11.

Answer: 11


4 0
4 years ago
Given: Triangle ABC, mmBC=24 cm, line segment AL- < bisector
Furkat [3]

The value of line AL is 21. 51cm

<h3>How to determine the length</h3>

To find line AL,

Using

Sin α = opposite/ hypotenuse to find line AB

Sin 90 = x/ 24

1 = x/24

Cross multiply

x = 24cm

Now, let's find line AC

Sin angle B = line AC/24

Note that to find angle B

angle A + angle B + angle C = 180

But angle B = 2 Angle A

x + 2x + 90 = 180

3x + 90 = 180

3x = 180-90

x = 30°

Angle B = 2 × 30 = 60°

Sin 60 = x/ 24

0. 8660 = x/24

Cross multiply

x = 24 × 0. 8660

x = 20. 78cm

We have the angle of A  in the given triangle to be divide into two by the bisector, angle A = 15°

To find line AL, we use

Cos = adjacent/ line AL

Cos 15 = 20. 78/ line AL

Line AL = 20. 78/ cos 15

Line AL = 20. 78 / 0. 9659

Line AL = 21. 51 cm

Thus, the value of line AL is 21. 51cm

Learn more about trigonometry ratio here:

brainly.com/question/24349828

#SPJ1

6 0
2 years ago
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