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Korolek [52]
3 years ago
8

Find the interest for each loan. $252 at 8% for 2 years: ________ $400 at 2% for 6 months:________ $5,000 at 3.5% for 1 year:___

________ $6,240 at 10% for 9 months: ___________
Mathematics
2 answers:
prisoha [69]3 years ago
4 0
Hi there! I can help you! Okay. So to find the amount of interest, we have to do the formula prt. That means multiply the principal, which is the initial amount of money, the rate, which is the interest rate, and the amount of time, which is usually in years. With that being said, here is how the answers turn out.

$252, 8% for 2 years: $40.32
$400, 2% for 6 months: $4
$5,000, 3.5% for 1 year: $175
$6,240, 10% for 9 months: $468

For the months, we just convert those numbers into decimal. 6 months is 1/2 a year, so it would be 0.5 and 9 months is 3/4 of a year, so that decimal would be 0.75. All you have to do is multiply the amount of money by percentage (you can do it by decimal form) by amount of time, and you’ll be good.
m_a_m_a [10]3 years ago
3 0

Answer:

$252, 8% for 2 years: $40.32

$400, 2% for 6 months: $4

$5,000, 3.5% for 1 year: $175

$6,240, 10% for 9 months: $468

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Alja [10]

1. The answer is 16^2, so B.

16 x 16 = 256

2. The answer is 17, so B.

Some of the factor of 68 are: 1, 2, 4, 17, 34 and 68.

3. The answer is 15, so B.

Only 15 is composite since it contains more than a factor, which are 3 and 5. The rest of the numbers are prime since they only contain a factor.

4. The answer is 2^2^3^7, so B.

The factor tree:

84

2 x 42

2 x 2 x 21

2 x 2 x 3 x 7

Hope this helps! :)

3 0
3 years ago
A parabola opening up or down has vertex (0, 0) and passes through (-6,-9).
Firlakuza [10]

Answer:

the formula is 1.5x^2

Step-by-step explanation:

Since the vertex is 0,0 h and k are both 0

then you plug in the -6 and -9 to the equation

a(-6)=-9

3/2(x)^2

hope that answers your question

4 0
3 years ago
Calculus 2 Master needed, evaluate the indefinite integral of: <img src="https://tex.z-dn.net/?f=%5Cint%5C%28%20%28lnx%29%5E2%7D
viva [34]

Answer:

\int (\ln(x))^2dx=x(\ln(x)^2-2\ln(x)+2)+C

Step-by-step explanation:

So we have the indefinite integral:

\int (\ln(x))^2dx

This is the same thing as:

=\int 1\cdot (\ln(x))^2dx

So, let's do integration by parts.

Let u be (ln(x))². And let dv be (1)dx. Therefore:

u=(\ln(x))^2\\\text{Find du. Use the chain rule.}\\\frac{du}{dx}=2(\ln(x))\cdot\frac{1}{x}

Simplify:

du=\frac{2\ln(x)}{x}dx

And:

dv=(1)dx\\v=x

Therefore:

\int (\ln(x))^2dx=x\ln(x)^2-\int(x)(\frac{2\ln(x)}{x})dx

The x cancel:

=x\ln(x)^2-\int2\ln(x)dx

Move the 2 to the front:

=x\ln(x)^2-2\int\ln(x)dx

(I'm not exactly sure how you got what you got. Perhaps you differentiated incorrectly?)

Now, let's use integrations by parts again for the integral. Similarly, let's put a 1 in front:

=x\ln(x)^2-2\int 1\cdot\ln(x)dx

Let u be ln(x) and let dv be (1)dx. Thus:

u=\ln(x)\\du=\frac{1}{x}dx

And:

dv=(1)dx\\v=x

So:

=x\ln(x)^2-2(x\ln(x)-\int (x)\frac{1}{x}dx)

Simplify the integral:

=x\ln(x)^2-2(x\ln(x)-\int (1)dx)

Evaluate:

=x\ln(x)^2-2(x\ln(x)-x)

Now, we just have to simplify :)

Distribute the -2:

=x\ln(x)^2-2x\ln(x)+2x

And if preferred, we can factor out a x:

=x(\ln(x)^2-2\ln(x)+2)

And, of course, don't forget about the constant of integration!

=x(\ln(x)^2-2\ln(x)+2)+C

And we are done :)

8 0
3 years ago
What number makes 3 and 71 divisible by 9?
Snezhnost [94]
3 only 
<span>7 only </span>
<span>1 only </span>
<span>1, 4, and 7 </span>
<span>do you mean which digit is added to 371 so that it is divisible by 3 </span>
<span>test for 3, sum of digits divisible by 3 </span>
<span>3 + 7 + 1 = 11 </span>
<span>if you add 3, 11 + 3 = 14 not divisible by 3 </span>
<span>if you add 7, 11+ 7 = 18 divisible by 3 </span>
<span>if you add 1, 11+ 1 = 12 divisible by 3 </span>
<span>if you add 1, 4, 7 divisible by 3 </span>
4 0
3 years ago
Need help solving for Y
den301095 [7]
I hope this helps you

5 0
3 years ago
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