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Tpy6a [65]
3 years ago
11

jerome bought 2 postcards and received $1.35 in change in quarters and dimes. If he got 6 coins back, how many of each coin did

he get
Mathematics
2 answers:
pychu [463]3 years ago
5 0
The answer could be 5 quarters and a dime, or 4 quarters, 1 dime, and 1 nickle.
kenny6666 [7]3 years ago
3 0
His coins would be 5 quarters and 1 dime
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Need help with 27 , 29, and 30. ASAP please this is due in 30 minutes
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6 0
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A baby cardinal weighs about 4.3 grams at birth. After 4 days it is 3.4 times as heavy. How much does it weigh after 4 days?
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8 0
2 years ago
The sum of 8 and joses score is 35 use the variable j yo represent josés score​
OLEGan [10]

Answer:

8 + j = 35

subtract 8 from both sides

j = 27

Step-by-step explanation:

8 0
3 years ago
A triangle has two sides of length 15 cm and 17 cm. Select all the values of its third side that would make it a right triangle
Natali [406]

Answer:

\sqrt{514} cm, 8cm, are both options

Step-by-step explanation:

For a right triangle one can find the length of the longest side by using the Pythagorean theorem. So there are two options I can think of that if the triangle is a right triangle will work. First remember what the Pythagorean theorem is : side a^2+side b^2=hypotenuse^2

The hypotenuse is the longest side of a right triangle. So if the sides that are 15 and 17 cm are not the longest sides then the formula would be:

15^{2} +17^2=c^2\\15^2+17^2=\sqrt{514}cm

But if 17cm is the longest side then:

a^2+15^2=17^2\\8^2+15^2=17^2\\a=8cm

Hope this helps!

4 0
3 years ago
Read 2 more answers
A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3
Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = nPk=\frac{n!}{(n-k)!}

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts =  5P4+4P2+8P3

=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468

So, this can be done in 468 ways.

7 0
3 years ago
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