The value of the quantity after 1 year, to the nearest hundredth is 4000.00
<h3>The exponential form of an equation</h3>
The standard exponential equation is eexpressed as:
![P(t)=P_0e^{kt}](https://tex.z-dn.net/?f=P%28t%29%3DP_0e%5E%7Bkt%7D)
Given the following parameters
![P_0=4000\\r =0.0005\\t = \frac{1}{50} =0.02 (yearly)](https://tex.z-dn.net/?f=P_0%3D4000%5C%5Cr%20%3D0.0005%5C%5Ct%20%3D%20%5Cfrac%7B1%7D%7B50%7D%20%3D0.02%20%28yearly%29)
Substitute into the formula to have:
![P(t)=4000e^{0.0005(0.02)}\\P(1)=4000e^{0.00001}\\P(1)=4000](https://tex.z-dn.net/?f=P%28t%29%3D4000e%5E%7B0.0005%280.02%29%7D%5C%5CP%281%29%3D4000e%5E%7B0.00001%7D%5C%5CP%281%29%3D4000)
Hence the value of the quantity after 1 year, to the nearest hundredth is 4000.00
Learn more on exponential equations here: brainly.com/question/12940982
This is your perfect answer
Step-by-step explanation:
Pressure = Force / Area
= 64N / 3.2m² = 20Pa. (2s.f.)
Answer:
4 feet × 16 feet × 25 feet
4 feet × 20 feet × 20 feet
and 4 feet × 40 feet × 10 feet