All categories

3 years ago

Can someone please help me? If g(x) = x2 - 5x + 2, find g(0).

Mathematics

1 answer:

Debora [2.8K]3 years ago

5 0

g(x) = x² - 5x + 2

You are looking for g(0). This means that you must replace all the x values in the equation above with 0

(0)² - 5(0) + 2

Now you need to solve according to the rules of PEMDAS:

(0)² - 5(0) + 2

0 - 5(0) + 2

0 - 0 + 2

0 + 2

g(0) = 2

Hope this helped!

~ Just a girl in love with Shawn Mendes

You might be interested in

Can you please show me how to do:

USPshnik [31]

Step-by-step explanation:

$6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6$

3 0

3 years ago

Read 2 more answers

Jacob buys 3 hot dogs and a $1 soda.he spent $5.50 in all.what is the cost of one hot dog?

Margaret [11]

It would be $1.50 because if the soda's $1 then subtract it and divide that by the quantity.

6 0

3 years ago

Read 2 more answers

A school with 340 students produces trash that fills 1,190 tall trash cans per week. If each student produces the same amount of

earnstyle [38]

3.5 trash cans a week

7 0

3 years ago

Marigold read the same number of books each month during the first half of the year.she read 30 books in all. write an equation

ivann1987 [24]

B=30 divided by 6
The answer is 5.

6 0

3 years ago

NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?

qwelly [4]

Answer:

Vertex is (-8, 4) not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

$y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4$

Complete the square by squaring half the coefficient of x and adding it in the space.

$(\frac{16}{2})^2=64$

Add 64 in the space you made, then compensate for that at the end of the expression by subtracting $-\frac{1}{8}(64)=-8$

$y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4$

The x-coordinate of the vertex is the opposite of +8, the number inside the parentheses. The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

8 0

3 years ago