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grin007 [14]
3 years ago
8

A pair of dice is rolled 20 times. what is the probability that a sum of 5 is rolled at least r times

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0
The probability of the sum of 5 is 5/20 or 1/4.
Solution:
Formula: P(A) = No. of favorable outcomes / Total no. of possible outcomes
P(A) = 5/20
P(A) = 1/4
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Carmen spent 88.00 at the mall the money she spent was 25% of the total amount she had in her wallet how much money did Carmen h
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Answer:

$352

Step-by-step explanation:

x = total money she had

spent 25% of x = 88

solve for x

x = 88/0.25

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57; 27; 72; 36; 61; 81; 45 From the numbers above, choose a prime factor​
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57

Step-by-step explanation:

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Determine the term life insurance amount per thousand on a 22-year-old female for a 5-year policy given that the face value of t
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We need to determine the term life insurance amount per thousand on a 22-year-old female for a 5-year policy given that the face value of the policy is $600,000 and the annual premium is $1332.

Since we are supposed to find the term life insurance amount per thousand, therefore, we will use the following formula:

\text{Term life insurance amount}=\frac{\text{Annual premium}}{\text{Face value of insurance}}*1000

Upon substituting the values of annual premium and face value of insurance, we get:

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4 0
3 years ago
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6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each
umka2103 [35]

The point of intersection is the point where lines intersect.

<em>There will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Given

<em />n = 35<em> --- the number of lines</em>

<em />d = 3<em> --- no three lines are concurrent</em>

<em />

When no three line are concurrent, it means that no three lines meet at the same point.

<u>So, the sequence of intersection is:</u>

  • <em>0 intersection for 1 line</em>
  • <em>1 intersection for 2 lines</em>
  • <em>3 intersections for 3 lines</em>
  • <em>6 intersections for 4 lines</em>

<em />

Following the above sequence, the number of intersections for n lines is:

n_k = \frac{n \times (n - 1)}{2}

In this case, n = 35.

So, we have:

n_k = \frac{35 \times (35 - 1)}{2}

n_k = \frac{35 \times 34}{2}

n_k = 35 \times 17

n_k = 595

<em>Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.</em>

<em />

Read more about lines of intersections at:

brainly.com/question/22368617

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