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Nuetrik [128]
3 years ago
14

Chromosomes are lined up in the middle of the cell during which phase of mitosis?

Biology
1 answer:
Katarina [22]3 years ago
8 0
Chromosomes are lined up in the middle of the cell during metaphase. 
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What would happen to an animal cell with an internal salt concentration of 70% if it were placed in a salt solution with a conce
Vlada [557]

Answer:

It will swell and eventually burst because water from the environment is flowing into the cell

Explanation:

This question is describing OSMOSIS, which is the movement of water from a region of high concentration to a region of low concentration across a semi-permeable membrane. The osmotic process is facilitated by the formation of an OSMOTIC GRADIENT i.e. difference in concentration between the two sides of the membrane.

In this case, an animal cell containing an internal salt concentration of 70% (hypertonic) were placed in a salt solution with a concentration of 20% (hypotonic), OSMOSIS will occur in the sense that water will move from where it is more concentrated (salt solution) into where it is less concentrated (animal cell), hence, the animal cell will SWELL AND EVENTUALLY BURST.

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3 years ago
Read the following scenarios carefully and explain how natural selection will occur in each.
IrinaK [193]

Answer:

The correct answer is - Noctural worms have the advantage over diurnal due to the fact that the nocturnal worms are burrowing during the feeding time of birds.

Explanation:

Natural selection is the process in which organisms adapt according to environmental changes to increase their survival rate. Natural selection leads to natural changes in different organisms.

In this case, diurnal worms are forced by the natural selection here to adapt to the change if they want to survive. Here, natural selection works for the nocturnal and against the diurnal.

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Explain how my model can be used to predict how changing the Earth’s tilt would impact seasons
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6 0
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What is the typical F2 ratio in the case of dominant epistasis?
inysia [295]

Answer:

12:3:1

Explanation:

<em>The typical F2 ratio in cases of dominant epistasis is 12:3:1.</em>

<u>The epistasis is a form of gene interaction in which an allele in one locus interacts with and modifies the effects of alleles in another locus</u>. There are different types of epistasis depending on the type of alleles that are interacting. These include:

  • Dominant/simple epistasis: Here, a dominant allele on one locus suppresses the expression of both alleles on another locus irrespective of whether they are dominant or recessive. Instead of the Mendelian dihybrid F2 ratio of 9:3:3:1, what is obtained is 12:3:1. Examples of this type of gene interaction are found in seed coat color in barley, skin color in mice, etc.
  • Other types of epistasis include <em>recessive epistasis (9:3:4), dominant inhibitory epistasis (13:3), duplicate recessive epistasis (9:7), duplicate dominant epistasis (15:1), and polymeric gene interaction (9:6:1).</em>
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