Solve for x. 4−(2x+4)=5 x=6 x=−52 x=−10 x=32
1 answer:
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2(4 + 2x) ≥ 5x + 5
First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4.
Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself.
Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.
Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3.
Fifth, we can switch sides now to get the result of this problem.
Answer:
First, we will need to expand our problem. Expanding is basically removing the parentheses. To do this, we will look at the first part of the problem to begin with. 2(4 + 2x). Since parentheses usually mean multiplication, we can start with 2(4). So, 2 × 4 = 8. We'll do the same thing with 2(2), 2 × 2 = 4.
Second, our next step is to subtract 4 from each side. We are trying to get the variable (x) on one side of the problem by itself.
Third, we can now simplify (5x) + 5 - (4). I put parentheses around what we are going to focus on. Subtract 5x - 4 to get 1, which can be put as the variable (x). Now we have, x + 5.
Fourth, let's subtract 5 from each side now. This will set up 8 - 5 which equals 3.
Fifth, we can switch sides now to get the result of this problem.
Answer:
There are 35 coupons in the jar.
The probability to choose <span>coupon for 1 month of extended membership is
.</span>
The probability to choose <span>coupon for 1.5 months of extended membership is
.
</span>
<span>Answer: With probability
a customer will get 30 days extended membership, </span>
with probability
a customer will get 450 days extended membership,
<span>with probability
a customer will get 60 days extended membership.</span>
The probability to choose coupon for 1 month of extended membership is
.
Together P(A)+P(B)+p(C)=1.
The probability to choose <span>coupon for 1 month of extended membership is
The probability to choose <span>coupon for 1.5 months of extended membership is
</span>
<span>Answer: With probability
with probability
<span>with probability
The probability to choose coupon for 1 month of extended membership is
Together P(A)+P(B)+p(C)=1.