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3 years ago

Sum of exterior angles in a equilateral triangle

Mathematics

1 answer:

poizon [28]3 years ago

8 0

Answer:

In the case of the equilateral triangle, , the exterior angle, plus 60 equals 180. Subtracting 60 from both sides of this equation gives us a value of equal to 120. This means that the exterior angle of an equilateral triangle is equal to 120 degrees. The sum of all the exterior angles is always 360 degrees.

Step-by-step explanation:

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A plane that carries mail makes a round trip each day from Chicago to New York. It makes 2 intermediate stops on the way to New

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Answer:

Step-by-step explanation:

7(d)

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3 years ago

10+200+0=——— what can you do with this

musickatia [10]

Answer:

210

Step-by-step explanation:

you can do 200 + 10 = 210

You can also do 200 + 1 x10

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3 years ago

Read 2 more answers

In a race competition the probability that Harry wins is 0.4, the probability that Krish wins is 0.2 and the probability that Jo

Leya [2.2K]

Answer:

jonny is the winner.

Step-by-step explanation:

No. of wins harry has = 0.4

No. of wins krish has = 0.2

No. of wins jonny has = 0.3

To find the prbability of harry and jonny = 0.4 + 0.3

= 0.7

Now to see who wins we have to add krish's wins and harry's win, because harry has the greatest number of wins.

krish = 0.2

harry = 0.4

= 0.6

now we have all three's score, so we will now see which is the greatest number.

krish= 0.6

harry = 0.4

jonny = 0.7

The greatest number is 0.7.

Hence, jonny is the winner!

HOPE IT HELPS PLZ MARK ME BRAINLIEST :D

3 0

3 years ago

Which of the following is a way that you would employ arithmetic in a real world situation?

otez555 [7]

Hey there! The answer is actually A. Choosing a grocery item based on a price per unit comparison.

I hope this helps you guys!

I have a screenshot attached as proof :)

4 0

3 years ago

Read 2 more answers

Two solutions to y'' – 2y' – 35y = 0 are yı = e, Y2 = e -5t a) Find the Wronskian. W = 0 Preview b) Find the solution satisfying

pashok25 [27]

Answer:

a. $w(t)=-12e^{2t}$

b. $y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}$

Step-by-step explanation:

We have a differential equation

y''-2 y'-35 y=0

Auxillary equation

$(D^2-2D-35)=0$

By factorization method we are finding the solution

$D^2-7D+5D-35=0$

$(D-7)(D+5)=0$

Substitute each factor equal to zero

D-7=0 and D+5=0

D=7 and D=-5

Therefore ,

General solution is

$y(x)=C_1e^{7t}+C_2e^{-5t}$

Let $y_1=e^{7t} \;and \;y_2=e^{-5t}$

We have to find Wronskian

$w(t)=\begin{vmatrix}y_1&y_2\\y'_1&y'_2\end{vmatrix}$

Substitute values then we get

$w(t)=\begin{vmatrix}e^{7t}&e^{-5t}\\7e^{7t}&-5e^{-5t}\end{vmatrix}$

$w(t)=-5e^{7t}\cdot e^{-5t}-7e^{7t}\cdot e^{-5t}=-5e^{7t-5t}-7e^[7t-5t}$

$w(t)=-5e^{2t}-7e^{2t}=-12e^{2t}$

a. $w(t)=-12e^{2t}$

We are given that y(0)=-7 and y'(0)=23

Substitute the value in general solution the we get

$y(0)=C_1+C_2$

$C_1+C_2=-7$ ....(equation I)

$y'(t)=7C_1e^{7t}-5C_2e^{-5t}$

$y'(0)=7C_1-5C_2$

$7C_1-5C_2=23$ ......(equation II)

Equation I is multiply by 5 then we subtract equation II from equation I

Using elimination method we eliminate $C_1$

Then we get $C_2=-\frac{5}{2}$

Substitute the value of $C_2$ in I equation then we get

$C_1-\frac{5}{2}=-7$

$C_1=-7+\frac{5}{2}=\frac{-14+5}{2}=-\frac{9}{2}$

Hence, the general solution is

b. $y(t)=-\frac{9}{2}e^{7t}-\frac{5}{2}e^{-5t}$

7 0

3 years ago