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3 years ago

The dimensions of triangle B are three times the dimensions of triangle A. The area of triangle A is 40.5 cm2.

Mathematics

1 answer:

zaharov [31]3 years ago

5 0

I think the answer is 121.5

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Solve (D^3-D^2-D-2)y=0

allsm [11]

(^3-^2+2)D=0

D^2+D^2+2D=0

2D^2+2D=0

a = 2; b = 2; c = 0;

Δ = b2-4ac

Δ = 22-4·2·0

Δ = 4

D1=−b−Δ√2aD2=−b+Δ√2a

Δ−−√=4√=2

D1=−b−Δ√2a=−(2)−22∗2=−44=−1

D2=−b+Δ√2a=−(2)+22∗2=04=0

8 0

3 years ago

Answer the question in the photo please

Kisachek [45]

Answer:

Brian because if you do the math correctly it should be Brian

8 0

3 years ago

Read 2 more answers

Please give me the answer for number 2 and 3

Finger [1]

2. 720 ÷ 12 = 60 × 5 = 300.

3 $48,780 ÷ 18 = $2,710 × 12 = $32,520.

Hope this helps

6 0

4 years ago

Solve for the length of BC

Talja [164]

Answer:

BC= 9cm

Step-by-step explanation:

You'll need to use the Pythagorean theorem:

a^2 + b^2 = c^2

12^2 + b^2 = 15^2

The slanted side of the triangle is always going to be 'c' because it is the longest side of the triangle.

Now simplify: 144 + b^2 = 225

I got these numbers because 12^2= 144 and 15^2= 225

Subtract. 225 - 144 = 81

Now find the square root of 81. The answer is 9.

3 0

3 years ago

Which is the equation of an ellipse centered at the origin with foci on x-axis, major axis of length 12 and minor axis of length

svp [43]

Answer:

$\frac{x^{2} }{36}+\frac{y^2}{16}=1$

Step-by-step explanation:

Center of the ellipse is at origin (0, 0)

So (h, k) = (0, 0)

Length of major axis = 12

2a = 12

⇒ a = 6

Length of minor axis = 8

⇒ 2b = 8

⇒ b = 4

Since focus is on the x-axis, so it's a horizontal ellipse.

Equation of the horizontal ellipse is in the form of,

$\frac{(x-h)^{2} }{a^2}+\frac{(y-k)^2}{b^2}=1$

By substituting the given values of a, b, and (h, k)

$\frac{(x-0)^{2}}{6^2}+\frac{(y-0)^2}{4^2}=1$

$\frac{x^{2} }{36}+\frac{y^2}{16}=1$

5 0

4 years ago