The dimensions of triangle B are three times the dimensions of triangle A. The area of triangle A is 40.5 cm2.

ASAP!!! Graphic DesignWorks purchased $15,000 worth of computers in 2005.

sergeinik [125]

Answer:

D. $3000

Step-by-step explanation:

Just did the test

6 0

3 years ago

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If mx=x+5/x-1 and n(x) = x – 3, which function has the same domain as (m*n)(x)

Ne4ueva [31]

Answer:c

Step-by-step explanation:

Given

$m\left ( x\right )=x+\frac{5}{x-1}$

and $n\left ( x\right )=x-3$

m of n is given by replacing x in $m\left ( x\right )$ by x-3

$m\left ( n\left ( x\right )\right )=x-3+\frac{5}{x-3-1}=x-3+\frac{5}{x-4}$

$m\left ( n\left ( x\right )\right )$ can take any value of x except x=4 because at x=4 function is not defined

and $h\left ( x\right )=\frac{11}{x-4}$ is also not defined for x=4 and can take any value of x

7 0

3 years ago

A sample of blood pressure measurements is taken for a group ofadults, and those values (mm Hg) are listed below. The values a

scoundrel [369]

Answer:

1. coefficient of variation(systolic) = 13.88%

2. coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

Step-by-step explanation:

1. Mean of systolic = ( 117+126+158+96+157+122+116+134+127+122)÷10

= 127.5

Standard Deviation of systolic = (((117-127.5)^2 +(126-127.5)^2+(158-127.5)^2+ (96-127.5)^2 + (157-127.5)^2 + (122-127.5)^2 + (116-127.5)^2 +(134-127.5)^2 +(127-127.5)^2 +( 122-127.5)^2) ÷ 10)^(0.5)

SD = 17.7

coefficient of variation(systolic)

= Standard Deviation of systolic /mean of systolic

= $\frac{17.7}{127.5} * 100$

coefficient of variation(systolic) = 13.88%

2. Mean of diastolic = ( 80+77+76+51+90+89+60+64+72+83) ÷ 10

= 74.2

Standard Deviation of diastolic = (((80-74.2)^2 +(77-74.2)^2+(76-74.2)^2+ (51-74.2)^2 + (90-74.2)^2 + (89-74.2)^2 + (60-74.2)^2 +(64-74.2)^2 +(72-74.2)^2 +(83-74.2)^2) ÷ 10)^(0.5)

SD = 12

coefficient of variation(diastolic)

= Standard Deviation of diastolic /mean of diastolic

= $\frac{12}{74.2} *100$

coefficient of variation(diastolic) = 16.2%

3. The coefficients of variation for each data set are within 5 percentage points of each other Therefore the systolic measurements vary signifcantly less than the diastolic

8 0

3 years ago

Calculate the number of kilograms of mercury required to fill a pool that is 20.0 m x 50.0 m x 10.0 m. The density of mercury is

malfutka [58]

Answer:

$m=135000000 Kg$

Step-by-step explanation:

To find the number of kilograms of mercury we need to find how to relate density, mass and, volume. For this we shall recall the density formula:

$\rho=\frac{m}{V}$

where $\rho$ is the density, $m$ is the mass and, $V$ is the volume.

We have the density and want to compute the mass so now we want to know the volume of the pool.

The volume of a rectangular pool is given by the fomula:

$V= (length)(heigh)(width)$ .

So for our pool

$V= (20)(50)(10)$ .

$V= 10000m^{3}$ .

Our density is in $g/mL$ , so the last thing we need to do before computing the mass is to express the density in $Kg/m^{3}$ (this is because we want our mass in $Kg$ and, we have our volume in $m^{3}$ ).